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When the smaller of two consecutive integers is added to five times the larger the result is 53. Find the integers?
6x + 5 = 53 6x = 48 x = 8 8 + 45 = 53 8 and 9
When the smaller of two consecutive integers is added to three times the larger result is 23?
this is a algebraic word problem: we know we have two consecutive integers so x + 1 = y and we know that the smaller one (x) added to three times the larger, the results is 23 so x + 3y = 23 substitute (x+1) for y: x + 3(x+1) = 23 4x + 3 = 23 4x = 20 x = 5 y = 6
When the smaller of two consecutive integers is added to three times the larger the result is 23 find the integer?
Let the integers by 'm' & 'm+1' m +3(m+1) = 23 m + 3m + 3 = 23 4m = 20 m = 5 Hence m+1 = 6
When the smaller of two consecutive integers is added to three times the larger the result is 31 find the integer?
Let x equal the smaller integer. Three times the larger is 3(x + 1) or 3x + 3. Added all together, 4x + 3 = 31. Solve for x. 4x = 28 x = 7 Check it. 7 + 24 = 31 It checks.
What are three consecutive odd integers whose sum is 336?
The sum of any three consecutive odd integers is going to give an odd result. It is impossible for the sum of an odd number of odd integers to equal an even number.
