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Let the integers be n and n + 1.n + 3(n+ 1) = 47

4n + 3 = 47

4n = 44

n = 11

n+ 1 = 12.

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9y ago

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11 and 12

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9y ago
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11 and 12.

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9y ago
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Q: When the smaller of the two consecutive integers is added to three times the larger the result is 47 Find the integers?
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