x=81
The sin of 30 is sqr(3)/2 so 6 * sqr(30) is 6 * sqr(3)/2 this is also 6/2 * sqr(3) which simplifies to 3 * sqr(3) which is approximately 5.19615242
Area is not measured in centimeter units. It may be guessed that the question should have indicated the area in square centimeters.The area of a regular pentagon is given as:A = s * s * sqr(25 + 10*(sqr(5)) / 4Solve for s:s = 2 * sqr (A / sqr(25 + 10*(sqr(5)))Insert the area of 600 square centimters:s = 2 * sqr (600 cm*cm / sqr(25 + 10*(sqr(5)))s = aproximately 19.67 cm
231 m2 is about 2,486.5 square feet.
sqr(-30) is i*sqr(30) We use i to represent the sqr(-1) because it is called an imaginary number. It takes an imagination to work with it. It is not fictitious.
110
54 = 625 (to find out sqr rt 625 then sqr rt again)
main() { sum=0; float avg=0.0; int sqr[10]; for(i=1;i<=10;i++) { sqr[i]=(i*i); } for(i=1;i<=10;i++) { sum=sum+sqr[i]; } avg=sum/10; dts it !!!
8(1st eight) +8(2nd eight)= 16-> sqr(16)=4 -> sqr(4)=2 ; 8(3rd eight)-2=6
2x2-2x=12x2-2x-1=0a=2 b=-2 c=-1x= (-b +- sqr(b2-4ac))/2ax= (2 +- sqr(4 + 8))/4x= (2 +- sqr(12))/4x = 1/2 +- sqr(12)/4x ~= .5 +- 0.8660x ~=-0.3660 or x ~= 1.3660
sqr(e/pi)
Square root of (18*18+80*80) sqr(324+6400) sqr(6724) 82
#include<stdio.h> #include<conio.h> #include<math.h> void main() { int a,s,e,sqr,digit,rev=0,d,r=0,sroot,i; clrscr(); printf("Enter starting limit:"); scanf("%d",&s); printf("Enter ending limit:"); scanf("%d",&e); printf("Adam number series:\n"); for(i=s;i<=e;i++) { a=i; sqr=i*i; while(sqr!=0) { digit=sqr%10; rev=rev*10+digit; sqr=sqr/10; } sroot=sqrt(rev); while(sroot!=0) { d=sroot%10; r=r*10+d; sroot=sroot/10; } if(r==a) printf("%d\n"a); sqr=0; digit=o; rev=0; d=0; sroot=0; r=0; } getch(); }