0
x=81
What else can I help you with?
What is 6 sin 30 equals?
The sin of 30 is sqr(3)/2 so 6 * sqr(30) is 6 * sqr(3)/2 this is also 6/2 * sqr(3) which simplifies to 3 * sqr(3) which is approximately 5.19615242
231 sqr meter to sqr feet?
231 m2 is about 2,486.5 square feet.
The area of a regular pentagon is 600 cm Calculate the length of one side of the pentagon?
Area is not measured in centimeter units. It may be guessed that the question should have indicated the area in square centimeters.The area of a regular pentagon is given as:A = s * s * sqr(25 + 10*(sqr(5)) / 4Solve for s:s = 2 * sqr (A / sqr(25 + 10*(sqr(5)))Insert the area of 600 square centimters:s = 2 * sqr (600 cm*cm / sqr(25 + 10*(sqr(5)))s = aproximately 19.67 cm
How would you write square root -30?
sqr(-30) is i*sqr(30) We use i to represent the sqr(-1) because it is called an imaginary number. It takes an imagination to work with it. It is not fictitious.
What are two numbers that multiplies to 100 and adds up to 10?
110
What number raised to the fourth power equals 625?
54 = 625 (to find out sqr rt 625 then sqr rt again)
Write a program to compute the average of the squares of the numbers from 1 to 10?
main() { sum=0; float avg=0.0; int sqr[10]; for(i=1;i<=10;i++) { sqr[i]=(i*i); } for(i=1;i<=10;i++) { sum=sum+sqr[i]; } avg=sum/10; dts it !!!
How do you get three eights to equal 6 you can't use any other numbers only inserting symbols?
8(1st eight) +8(2nd eight)= 16-> sqr(16)=4 -> sqr(4)=2 ; 8(3rd eight)-2=6
What is the area of the inverse circle?
sqr(e/pi)
Solve this quadratic equation using the quadratic formula 2x2 - 2x equals 1?
2x2-2x=12x2-2x-1=0a=2 b=-2 c=-1x= (-b +- sqr(b2-4ac))/2ax= (2 +- sqr(4 + 8))/4x= (2 +- sqr(12))/4x = 1/2 +- sqr(12)/4x ~= .5 +- 0.8660x ~=-0.3660 or x ~= 1.3660
What is thr length of the hypotenuse of a right triangle with legs 18 and 80?
Square root of (18*18+80*80) sqr(324+6400) sqr(6724) 82
Number generation for Adam in c?
#include<stdio.h> #include<conio.h> #include<math.h> void main() { int a,s,e,sqr,digit,rev=0,d,r=0,sroot,i; clrscr(); printf("Enter starting limit:"); scanf("%d",&s); printf("Enter ending limit:"); scanf("%d",&e); printf("Adam number series:\n"); for(i=s;i<=e;i++) { a=i; sqr=i*i; while(sqr!=0) { digit=sqr%10; rev=rev*10+digit; sqr=sqr/10; } sroot=sqrt(rev); while(sroot!=0) { d=sroot%10; r=r*10+d; sroot=sroot/10; } if(r==a) printf("%d\n"a); sqr=0; digit=o; rev=0; d=0; sroot=0; r=0; } getch(); }
