(x-9)(x+1)
x^2 - 8x - 9
x2-6x+9 = (x-3)(x-3) when factorised.
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
(x + 7)(x - 9)
x2+8x+9 = -7 x2+8x+9+7 = 0 x2+8x+16 = 0 (x+4)(x+4) = 0 Therefore: x = -4 and also x = -4 (they both have equal roots)
1
(x - 9)(x + 1)
x2 + 8x - 9 = 0(x + 9) (x - 1) = 0(x + 9) = 0 . . . . . x = -9(x - 1) = 0 . . . . . x = 1
x=-1
(x + 9)(x - 1)
(x + 9)(x - 1)
When factored it is: (x+9)(x-1)