X2 + 8x + 16 = 10x +16x2 + 8x + 16=2x + 8x + 16=10x + 16
x2 + 8x - 20 = (x - 2)(x + 10).
x2 + 8x + 15 = (x + 3)(x + 5)
Also 64
-8x-9+(-18) -8x-9-18 -8x-27 is your simplified answer
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
x2+8x+9 = -7 x2+8x+9+7 = 0 x2+8x+16 = 0 (x+4)(x+4) = 0 Therefore: x = -4 and also x = -4 (they both have equal roots)
1
(x-9)(x+1)
(x - 9)(x + 1)
x2 + 8x - 9 = 0(x + 9) (x - 1) = 0(x + 9) = 0 . . . . . x = -9(x - 1) = 0 . . . . . x = 1
x=-1
(x + 9)(x - 1)
(x + 9)(x - 1)
When factored it is: (x+9)(x-1)
The answer is No Solution, Assuming the problem is [ x2 = 8x - 90 ]: x2 = 8x - 90 [ or, 2x = 8x - 90 ] 10x = (-90) x = (-9) So, lets plug in "x". 2(-9) = 8(-9) - 90 (-18) = (-72) - 90 (-18) = (-162) And thus, there is no solution.
2x+6x=-9 => 8x=-9=> x=-8/9