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(x3 + x2 + x + 1)/(x -1) (using the long division)
x2(x - 1) = x3 - x2
x3 + x2 + x + 1 - (x3 - x2) = 2x2 + x + 1
2x(x - 1) = 2x2 - 2x
2x2 + x + 1 - (2x2 - 2x) = 3x + 1
3(x - 1) = 3x - 3
3x + 1 - (3x - 3) = 4 (the remainder)
(x3 + x2 + x + 1)/(x -1) = x2 + 2x + 3 + 4/(x -1)
(1x3 + 1x2 + 1x + 1)/(x -1) (using the synthetic division)
(the constant of the divisor) 1] 1 1 1 1 (the coefficients of the dividend)
The coefficients of the quotient:
1
1 + 1*1 = 2
1 + 2*1 = 3
Since the degree of the first term of the quotient is one less than the degree of the first term of the dividend, the quotient is x2 + 2x + 3.
The remainder
1 + 3*1 = 4
(x3 + x2 + x + 1)/(x -1) = x2 + 2x + 3 + 4/(x -1)
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How do you compute quadratic equation using java?
What do you mean by "compute"? Do you want to graph it? Factor it? Calculate it's function given a set of points that lie on it? If you're looking to compute the function given three points that fall on the parabola, then I have just the code for you. If you're given three points, (x1, y1), (x2, y2) and (x3, y3), then you can compute the coefficients of your quadratic equation like this: a = (y1 * (x2 - x3) + y2 * (x3 - x1) + y3 * (x1 - x2)) / (x1 * x1 * (x2 - x3) + x2 * x2 * (x3 - x1) + x3 * x3 * (x1 - x2)) b = (y1 - y2) / (x1 - x2) - a * (x1 + x2); c = y1 - (x1 * x1) * a - x1 * b; You now can calculate the y co-ordinate of any point given it's x co-ordinate by saying: y = a * x * x + b * x + c;
How do you create a quadratic model from a list of data x values 140 150 170 175 205 y values 1.4 1.25 0.93 0.78 0.43 please please please help?
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The mean of 10 observations is 21 If each score is divided by 3 find the new mean?
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How do you compute quadratic equation using java?
What do you mean by "compute"? Do you want to graph it? Factor it? Calculate it's function given a set of points that lie on it? If you're looking to compute the function given three points that fall on the parabola, then I have just the code for you. If you're given three points, (x1, y1), (x2, y2) and (x3, y3), then you can compute the coefficients of your quadratic equation like this: a = (y1 * (x2 - x3) + y2 * (x3 - x1) + y3 * (x1 - x2)) / (x1 * x1 * (x2 - x3) + x2 * x2 * (x3 - x1) + x3 * x3 * (x1 - x2)) b = (y1 - y2) / (x1 - x2) - a * (x1 + x2); c = y1 - (x1 * x1) * a - x1 * b; You now can calculate the y co-ordinate of any point given it's x co-ordinate by saying: y = a * x * x + b * x + c;
How many times in a twelve hour period does the sum of the digits on a digital clock equal six and prove it?
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