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(x^(3) + X^(2) + x + 1) / ( x + 1)

Factor

[x^(2))(x + 1) + ( x +1) ] / ) x + 1)

[(x^(2) + 1 )(x + 1)] / ( x + 1)

Cancel down by 'x + 1'

Hence

x^(2) + 1 The Answer!!!! (NB This term does NOT factor).

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lenpollock

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1w ago

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