0
(x^(3) + X^(2) + x + 1) / ( x + 1)
Factor
[x^(2))(x + 1) + ( x +1) ] / ) x + 1)
[(x^(2) + 1 )(x + 1)] / ( x + 1)
Cancel down by 'x + 1'
Hence
x^(2) + 1 The Answer!!!! (NB This term does NOT factor).
What else can I help you with?
What is the quotient and remainder of 4x4 -x3 plus 17x2 plus 11x plus 4 when divided by 4x plus 3?
Dividend: 4x^4 -x^2 +17x^2 +11x +4 Divisor: 4x +3 Quotient: x^3 -x^2 +5x -1 Remainder: 7
How do you factor the trinomial x3 - 20x2 plus 19x?
Divide by x: x(x2 - 20x + 19); = x(x -1)(x - 19)
What is x cubed -3x squared -x -1 divided by x plus 2?
x3 -3x2 -x - 1 divided by x+2 equals x2-5x+9 remainder -19 It's difficult to show how to work it out on this computer but division with algebra has a lot in common with doing long division with integers.
Integral of -x 2?
The integral of -x2 is -1/3 x3 .
Real root of x3-2x plus 1 in newton raphson method?
By x3 I assume that you mean x3. In which case f(x)=x3-2x+1, and f'(x)=3x2-2. Therefore our iteration formula is: xn+1=xn- (xn3-2xn+1)/(3xn2-2) Starting with x0=0 we get: x1=0.5 x2=0.6 x3=0.617391304 x4=0.618033095 x5=0.618033988 x6=0.618033988 Starting with x0=0.9 we get: x1=1.065116279 x2=1.009457333 x3=1.000255451 x4=1.000000195 x5=1 x6=1 Starting with x0=-1.5 we get: x1=-1.631578947 x2=-1.618183589 x3=-1.618034007 x4=-1.618033989 x5=-1.618033989 The 3 real roots to f(x) are x=-1.618033989, x=0.618033988, and x=1
What is the factor of x3 plus x2 plus 4x plus 4?
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
X3 plus x2 minus 6x plus 4?
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
How do you Factor x cubed plus one divided by x plus one?
x3 + 1 = (x + 1)(x2 - x + 1) The x + 1's cancel out, leaving x2 - x + 1
Factor x5 plus x2?
x2(x3 + 1) is the best you can do there.
Write a c plus plus program to find the sum of series S equals 1 plus x2 plus x3 plus x3. plus xn?
(xn+2-1)/(x2-1)
Factor by grouping 3-3x plus x2-x3?
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
What is x plus 4 divided by x3 -11x plus 20?
(x + 4) / (x3 - 11x + 20) = (x + 4) / (x2 + 4x - 5)(x + 4) = 1 / (x2 + 4x - 5) = 1 / (x + 5)(x - 1), where x ≠ -4
How do you solve x-1 plus x2-x plus x3-x2 plus x4-x3?
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
How do you factor x3 plus 1?
x3 + 1 = x3 + x2 - x2 - x + x + 1 = x2(x + 1) - x(x + 1) +1(x + 1) = (x + 1)(x2 - x + 1)
What are the quotient and remainder when x cubed plus 3x squared plus 6x plus 1 is divided by x plus 1?
x3+3x2+6x+1 divided by x+1 Quotient: x2+2x+4 Remaider: -3
Integral of 1 plus x2?
The integral of 1 + x2 is x + 1/3 x3 + C.
What is the answer to x cubed plus 3x squared plus 3x plus 2 divided by x plus 2?
x3+3x2+3x+2 divided by x+2 equals x2+x+1
