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(x3 + x2 + x + 1)/(x -1) (using the long division)
x2(x - 1) = x3 - x2
x3 + x2 + x + 1 - (x3 - x2) = 2x2 + x + 1
2x(x - 1) = 2x2 - 2x
2x2 + x + 1 - (2x2 - 2x) = 3x + 1
3(x - 1) = 3x - 3
3x + 1 - (3x - 3) = 4 (the remainder)
(x3 + x2 + x + 1)/(x -1) = x2 + 2x + 3 + 4/(x -1)
(1x3 + 1x2 + 1x + 1)/(x -1) (using the synthetic division)
(the constant of the divisor) 1] 1 1 1 1 (the coefficients of the dividend)
The coefficients of the quotient:
1
1 + 1*1 = 2
1 + 2*1 = 3
Since the degree of the first term of the quotient is one less than the degree of the first term of the dividend, the quotient is x2 + 2x + 3.
The remainder
1 + 3*1 = 4
(x3 + x2 + x + 1)/(x -1) = x2 + 2x + 3 + 4/(x -1)
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How do you compute quadratic equation using java?
What do you mean by "compute"? Do you want to graph it? Factor it? Calculate it's function given a set of points that lie on it? If you're looking to compute the function given three points that fall on the parabola, then I have just the code for you. If you're given three points, (x1, y1), (x2, y2) and (x3, y3), then you can compute the coefficients of your quadratic equation like this: a = (y1 * (x2 - x3) + y2 * (x3 - x1) + y3 * (x1 - x2)) / (x1 * x1 * (x2 - x3) + x2 * x2 * (x3 - x1) + x3 * x3 * (x1 - x2)) b = (y1 - y2) / (x1 - x2) - a * (x1 + x2); c = y1 - (x1 * x1) * a - x1 * b; You now can calculate the y co-ordinate of any point given it's x co-ordinate by saying: y = a * x * x + b * x + c;
How do you create a quadratic model from a list of data x values 140 150 170 175 205 y values 1.4 1.25 0.93 0.78 0.43 please please please help?
The step-work involved in proving this would be too long and detailed to show here, but the end result is this: We're given three verticies, defined by the points (x1, y1), (x2, y2), and (x3, y3). We want to use them to define a parabola in this format: f(x) = ax2 + bx + c We can find our a, b and c coefficients with the following equations: a = [y1(x2 - x3) + y2(x3 - x1) + y3(x1 - x2)] / [x12(x2 - x3) + x22(x3 - x1) + x32(x1 - x2)] b = (y1 - y2) / (x1 - x2) - a(x1 + x2) c = y1 - a(x12) - b(x1)
How do find the probability of distribution Let Y equals X1 - X2 plus 2x3 Find Pr Y1.5?
This question can only be answered if the probability distribution functions of X1, X2 and X3 are known. They are not and so the question cannot be answered.
X3 plus x2 minus 6x plus 4?
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
The mean of 10 observations is 21 If each score is divided by 3 find the new mean?
The new mean would be 7. The mean is the average of the data. (x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10=21 [(x1/3)+(x2/3)+(x3/3)+(x4/3)+(x5/3)+(x6/3)+(x7/3)+(x8/3)+(x9/3)+(x10/3)]/10=? [(1/3)(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)]/10=? [(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10]/3= 21/3=7
What is X3 plus X2 plus X plus 1 divided by X 1?
2x2+7/x1
How do you compute quadratic equation using java?
What do you mean by "compute"? Do you want to graph it? Factor it? Calculate it's function given a set of points that lie on it? If you're looking to compute the function given three points that fall on the parabola, then I have just the code for you. If you're given three points, (x1, y1), (x2, y2) and (x3, y3), then you can compute the coefficients of your quadratic equation like this: a = (y1 * (x2 - x3) + y2 * (x3 - x1) + y3 * (x1 - x2)) / (x1 * x1 * (x2 - x3) + x2 * x2 * (x3 - x1) + x3 * x3 * (x1 - x2)) b = (y1 - y2) / (x1 - x2) - a * (x1 + x2); c = y1 - (x1 * x1) * a - x1 * b; You now can calculate the y co-ordinate of any point given it's x co-ordinate by saying: y = a * x * x + b * x + c;
How many times in a twelve hour period does the sum of the digits on a digital clock equal six and prove it?
notation: natural numbers = 0,1, 2, 3, 4, 5, ....., (some define it without the zero, though) <= means smaller than or equal to, {} is set notation and means a set of numbers : (such that) then some condition. For example {x: x is not a duck} is the set of all things not a duck. Our goal is to prove that there are 21 different times. let x1 = hours, x2 = tens of minutes, x3 = minutes. We are going to prove the statement about the set {x1, x2,x3: 1<=x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6}. It will be taken by assumption that this set is the set of digital clock combinations that add up to 6. So then, we must prove that there are unique 21 elements in the set {x1 + x2 + x3 : 1<= x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6}. {x1 , x2 , x3 : 1<= x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6} = {x1 , x2 , x3 : 1<= x1 <= 6, 0<= x2<=5, 0<=x3 <= 5, x1 + x2 + x3 = 6} because x3<=6, and because if x1 >=1, then x2 + x3 <=5, and x3, x2 >= 0 , so surely x3, x2 <= x5. Either x1 = 1, 2, 3, 4, 5, or 6. Next, x1 + x2 + x3 = 6, so x2 + x3 = 6 - x1. There are n+1 natural numbers between 0 and n (I'm being lazy and not proving this, but the proof would be so much longer if I proved it), and since 0 <= x2 <= 5 <= 6-x1, there are at most 6-x1+1 values of x2 for each value of x1. When x1 = 1, there are a maximum of 6, when x1 = 2, there are 6-2+1 = 5, when x1 = 3, there are 6-3+1 = 4, when x1 = 3, there are 3, then 2, and then 1. Summing this up gives us a maximum of 21. So it is at most 21 and at least 21, so exactly 21.
What do you mean by linearity in parameter and linearity in model?
Any model can be linear/nonlinear. Linearity can be in parameters or in variables. In Y=a+ b*x1 + c*x2 + d*x3 the model is linear in both parameters (b,c,d) and variables(x1,x2,x3) In Y=a+ (b+c)x1 + c*x2 + d*x3 the model is nonlinear in parameters (b,c,d) and linear in variables(x1,x2,x3) In Y=a+ bx1 + c*x2*x3 + d*x3 the model is linear in parameters (b,c,d) and nonlinear in variables(x1,x2,x3) In Y=a+ bx1 + c*x2*x3 + exp(b+d)*x3 the model is nonlinear in parameters (b,c,d) and nonlinear in variables(x1,x2,x3)
If you have Arceus or regigigas i will find almost any shiny Pokemon that is not legendary and trade it for one of them?
i have no idea what your talking about (Empoleonking) you mean you want to trade any shiny Pokemon for a Regigigas or a Arceus? (empoleonking) yep as long as its not legendary cuz i relly want arceus and regigigas (filmore85) here are all my shinys psyduck x4, dratini x2, gyarados x4, bronzong x1, seaking x2, machop x1, larvitar x1, geodude x4, skarmory x1, camerupt x3, pelipper x1, golduck x2, shinx x1, staravia x1, shellos (pink) x3, graveler x2, banette x1, snover x2, sneasel x7, bronzor x5, gible x1, raichu x1, bidoof, x2, bibarel x1, rhydon x2, weezing x1, numel x1, machoke x2, magcargo x1, meditite x3, madicham x2, kricketune x2, fearow x1, gastradon(pink) x3, floatzel x2, ditto x3, chingling x1, cleffa x1, nosepass x2, whiscash x4, zubat x2, illumise x1, dugtrio x2, hippopotas x1, unown x3. (filmore85) i also do requests if you have any.my friend code is 0603 8229 6574 (filmore85)
Comparison of Big-M method and two phase methods in solving linear programming problem?
use two phase method s.t x1+x2+x3>=3 -x1+2x2>=2 -x1+5x2+x3<=4 x1,x2,x3>=0
Find number of integer solution of X1 x2 x324?
find number of integer solution of X1+x2+x3=24
What is in a flaming dark light deck?
This deck contains. Monsters Flamvell firedog x2 flamvell magician x3 Flamvell guard x2 masked dragon x3 dread dragon x2 majestic dragon x2 worm caratos x2 worm dimikles x2 worm gulse x1 mystic tomato x3 changer synchron x2 reptilianne naga x2 drill barnicle x1 spells pot of avarice x1 pot of benevolence x2 monster reborn x1 cards of consonence x1 scapegoat x1 stardust shimmer x2 dark hole x1 heavy storm x1 burden of the mighty x1 crashbug road x2 swords of revealing light x1 spirit burner x1 Traps parallel selection x2 bottomless trap hole x2 trap hole x2 threating roar x2 call of the huanted x1 shadow spell x1 starlight road x2 urgent tuning x2 magic cylinder x1
How do you create a quadratic model from a list of data x values 140 150 170 175 205 y values 1.4 1.25 0.93 0.78 0.43 please please please help?
The step-work involved in proving this would be too long and detailed to show here, but the end result is this: We're given three verticies, defined by the points (x1, y1), (x2, y2), and (x3, y3). We want to use them to define a parabola in this format: f(x) = ax2 + bx + c We can find our a, b and c coefficients with the following equations: a = [y1(x2 - x3) + y2(x3 - x1) + y3(x1 - x2)] / [x12(x2 - x3) + x22(x3 - x1) + x32(x1 - x2)] b = (y1 - y2) / (x1 - x2) - a(x1 + x2) c = y1 - a(x12) - b(x1)
What is -x3 plus 75x-250 divided by x plus 10?
(-x3 + 75x - 250) / (x + 10) = x2 - 10x - 25
What is the best Yu-Gi-Oh warrior deck with elemental or destiny heroes?
I'd say definitely Eheros! My ehero deck is pretty awesome so this is my recipe: Monsters . Bladedge x2 . Clayman x2 . Avian x3 . Sparkman x3 . Wildheart x3 . Burstinatrix x3 . Woodsman x1 . Heat x1 . Stratos x1 . Wroughtweiler x1 . King of the swamps x2 Fusion monsters . Phoenix enforcer x1 . Shinig flare wingman x1 . Tera Firma x1 . Inferno x1 . Rampart blaster x2 . Wildedge x2 . Shining Phoenix enforcer x1 . Flame wingman x1 . Thunder Giant x1 Spells . O-Oversoul x1 . Mystical sace typhoon x1 . Fusion gate x2 . Skyscraper x1 . Fusion sage x1 . Super polymerization . Polymerization x2 . Future Fusion x1 . R-Righteous Justice x1 . E-Emergency call x3 Traps . Threatening roar x1 . Elemental Recharge x1 . Mirror force x1 . A hero emerges x1 . Magical cylinder x1 . Hero blast x1 . Waboku x1 It works for me and I normally fusion summon on my w1st or 2nd turn. :)
How do you beat level 29 B-Cubed?
okay... took me ages to figure out how to finish it but... up(X3), Right(X5), Up(X2), Left(X1), Down(X4), Right(X2), Down(X1), Left(X1), Right(X1), Down(X1), Left(X1), Down(X1), Right(X1), Down(X1), Left(X1), Down(X3), Right(X2), Down(X1), Right(X1), Down(X2), Left(X2), Up(X1), Right(X1), Down(X4), Right(X1), Up(X2), Left(X2), Down(X2), Right(X1) and finally Up(X1) :) code for level 30 is 676534
