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(x3 + x2 + x + 1)/(x -1) (using the long division)
x2(x - 1) = x3 - x2
x3 + x2 + x + 1 - (x3 - x2) = 2x2 + x + 1
2x(x - 1) = 2x2 - 2x
2x2 + x + 1 - (2x2 - 2x) = 3x + 1
3(x - 1) = 3x - 3
3x + 1 - (3x - 3) = 4 (the remainder)
(x3 + x2 + x + 1)/(x -1) = x2 + 2x + 3 + 4/(x -1)
(1x3 + 1x2 + 1x + 1)/(x -1) (using the synthetic division)
(the constant of the divisor) 1] 1 1 1 1 (the coefficients of the dividend)
The coefficients of the quotient:
1
1 + 1*1 = 2
1 + 2*1 = 3
Since the degree of the first term of the quotient is one less than the degree of the first term of the dividend, the quotient is x2 + 2x + 3.
The remainder
1 + 3*1 = 4
(x3 + x2 + x + 1)/(x -1) = x2 + 2x + 3 + 4/(x -1)
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How do you compute quadratic equation using java?
What do you mean by "compute"? Do you want to graph it? Factor it? Calculate it's function given a set of points that lie on it? If you're looking to compute the function given three points that fall on the parabola, then I have just the code for you. If you're given three points, (x1, y1), (x2, y2) and (x3, y3), then you can compute the coefficients of your quadratic equation like this: a = (y1 * (x2 - x3) + y2 * (x3 - x1) + y3 * (x1 - x2)) / (x1 * x1 * (x2 - x3) + x2 * x2 * (x3 - x1) + x3 * x3 * (x1 - x2)) b = (y1 - y2) / (x1 - x2) - a * (x1 + x2); c = y1 - (x1 * x1) * a - x1 * b; You now can calculate the y co-ordinate of any point given it's x co-ordinate by saying: y = a * x * x + b * x + c;
How do you create a quadratic model from a list of data x values 140 150 170 175 205 y values 1.4 1.25 0.93 0.78 0.43 please please please help?
The step-work involved in proving this would be too long and detailed to show here, but the end result is this: We're given three verticies, defined by the points (x1, y1), (x2, y2), and (x3, y3). We want to use them to define a parabola in this format: f(x) = ax2 + bx + c We can find our a, b and c coefficients with the following equations: a = [y1(x2 - x3) + y2(x3 - x1) + y3(x1 - x2)] / [x12(x2 - x3) + x22(x3 - x1) + x32(x1 - x2)] b = (y1 - y2) / (x1 - x2) - a(x1 + x2) c = y1 - a(x12) - b(x1)
How do find the probability of distribution Let Y equals X1 - X2 plus 2x3 Find Pr Y1.5?
This question can only be answered if the probability distribution functions of X1, X2 and X3 are known. They are not and so the question cannot be answered.
X3 plus x2 minus 6x plus 4?
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
The mean of 10 observations is 21 If each score is divided by 3 find the new mean?
The new mean would be 7. The mean is the average of the data. (x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10=21 [(x1/3)+(x2/3)+(x3/3)+(x4/3)+(x5/3)+(x6/3)+(x7/3)+(x8/3)+(x9/3)+(x10/3)]/10=? [(1/3)(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)]/10=? [(x1+x2+x3+x4+x5+x6+x7+x8+x9+x10)/10]/3= 21/3=7
