0
if:
y = -2x + 3
then:
if y = 0:
0 = -2x + 3
2x = 3
x = 3/2
if x = 0:
y = -2(0) + 3
y = 3
So the x-intercept is at {0, 3}, and the y-intercept is at {3/2, 0}
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∙ 14y ago
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What is the y-intercept for line 3y plus 2x equals -x plus 5?
3y+2x = -x+5 y = -x+5/3 So the y intercept is 5/3
What is the x and y intercept of Y equals -2x plus 3?
x intercept: (1.5, 0) y intercept: (0, 3)
Given 2x plus y equals 12 find the x-intercept?
At the x-intercept, y = 0 So, from the equation, 2x + 0 = 12 or x = 6 So the x-intercept is (6,0)
What is the intercept of the line 2x-3y plus 50?
To find the intercept of the line 2x - 3y + 50, we need to set one of the variables to zero. The x-intercept occurs when y is zero, so we can solve for x by setting y=0: 2x - 3(0) + 50 = 0. Simplifying, we get 2x + 50 = 0, which gives x = -25. Therefore, the intercept is (-25, 0).
What is the x-intercept of the line whose equation is 2x-3y equals 0?
2x - 3y = 0 y = 2x/3 (at x-intercepts, y = 0) therefore, 2x/3 = 0 x = 0. x = 0 is the x- intercept
What is the x and y intercepts for 2x plus y equals -6?
-4
What is the y-intercept for line 3y plus 2x equals -x plus 5?
3y+2x = -x+5 y = -x+5/3 So the y intercept is 5/3
What is the x and y intercept of Y equals -2x plus 3?
x intercept: (1.5, 0) y intercept: (0, 3)
What is the x intercept of y equals 2x plus 3?
The x-interceptin is where the graph crosses the y-axis, which is where y equals 0: 0 = 2x + 3 2x = -3 x = -3/2 So the x intercept is as x = -3/2 (and y = 0).
What are the intercepts of the line 2x plus 4y equals 12?
x-intercept: 6; y-intercept: 3
What is the y and x intercept for the equation 2x plus 3y equals 12?
2x + 3y = 12For the y-intercept, x=0:2(0) + 3y = 123y = 12y = 4Therefore, the y-intercept is at y=4, or (0,4)For the x-intercept, y=0:2x + 3(0) = 122x = 12x = 6Therefore, the x-intercept is at x=46, or (6,0)
What is the x-intercept of y equals 2x plus 5?
The x intercept is where y = 0 y = 2x +5 = 0 2x + 5 = 0 2x = -5 x = -5/2 = -2.5
What are the X and Y intercept forms for 2X plus 3Y equals A?
Set y = 0: So 2x =a ie x = a/2. So the x-intercept is (a/2, 0) Set x = 0: So 3y = a ie y = a/3. So the y intercept is (0, a/3)
Given 2x plus y equals 12 find the x-intercept?
At the x-intercept, y = 0 So, from the equation, 2x + 0 = 12 or x = 6 So the x-intercept is (6,0)
Where does 2x plus 3y equals 24 cut the x- axis?
We should always start with slope-intercept form: 2x + 3y = 24 3y = -2x + 24 y = -2x/3 + 8 Once in this form we see that our y-axis intercept is 8. To find our x-axis intercept, we solve the equation substituting 0 for y: 0 = -2x/3 + 8 -8 = -2x/3 x = (-8)(-3/2) x = 24/12 x = 12
What is the intercept of the line 2x-3y plus 50?
To find the intercept of the line 2x - 3y + 50, we need to set one of the variables to zero. The x-intercept occurs when y is zero, so we can solve for x by setting y=0: 2x - 3(0) + 50 = 0. Simplifying, we get 2x + 50 = 0, which gives x = -25. Therefore, the intercept is (-25, 0).
What is the x-intercept of the line whose equation is 2x-3y equals 0?
2x - 3y = 0 y = 2x/3 (at x-intercepts, y = 0) therefore, 2x/3 = 0 x = 0. x = 0 is the x- intercept
