if:
y = -2x + 3
then:
if y = 0:
0 = -2x + 3
2x = 3
x = 3/2
if x = 0:
y = -2(0) + 3
y = 3
So the x-intercept is at {0, 3}, and the y-intercept is at {3/2, 0}
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x intercept: (1.5, 0) y intercept: (0, 3)
3y+2x = -x+5 y = -x+5/3 So the y intercept is 5/3
At the x-intercept, y = 0 So, from the equation, 2x + 0 = 12 or x = 6 So the x-intercept is (6,0)
To find the intercept of the line 2x - 3y + 50, we need to set one of the variables to zero. The x-intercept occurs when y is zero, so we can solve for x by setting y=0: 2x - 3(0) + 50 = 0. Simplifying, we get 2x + 50 = 0, which gives x = -25. Therefore, the intercept is (-25, 0).
2x - 3y = 0 y = 2x/3 (at x-intercepts, y = 0) therefore, 2x/3 = 0 x = 0. x = 0 is the x- intercept