If you mean: a(a+4) then it is the same as a^2+4a
In a heterozygous cross (e.g., Aa x Aa), the possible genotypes of the offspring are AA, Aa, and aa. The probability of having two offspring with the same genotype can be calculated as follows: the probabilities of each genotype are 1/4 for AA, 1/2 for Aa, and 1/4 for aa. Thus, the probability that both offspring have the same genotype is the sum of the probabilities of each genotype occurring twice: (1/4 * 1/4) + (1/2 * 1/2) + (1/4 * 1/4) = 1/16 + 1/4 + 1/16 = 5/16. Therefore, there is a 5/16 chance that both offspring will have the same genotype.
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
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yo mama!!:0 that's who he/she is going out with a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a
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It completely depends on the type of defect;if it is X recessive or if it is not X recessive at all. For example: Consider two healthy sisters;one of them with chromosomal defect that doesn't show it: Aa&AA and the father Aa: Aa*Aa:1/2 Aa,1/4 aa,1/4AA AA*Aa:1/2AA,1/2Aa As we see the first sister may have a defective child but the second one may never have a defective child.
Aa, aaa, c,d
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