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From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
50% will be tall
The probability that an offspring will have wrinkled seeds is 2 in 4 or 50%
It depends. If it's a heterozygous cross, (Tt x Tt), there's a 25% chance. If it's a homozygous dominant cross (TT x TT), the chance is 0%. Neither parent has the alleles for a recessive trait, so none of their offspring can have the recessive trait. If it's a homozygous recessive cross (tt x tt), there's a 100% chance. The only alleles the parents can pass on are recessive.
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
The genotype of the tall pea plant is heterozygous
To determine the genotype of an individual who is heterozygous for a trait, you would need to perform a genetic cross with a homozygous recessive individual. By observing the phenotypes of the offspring, you can deduce the genotype of the heterozygous individual. This can help determine if the heterozygous individual is carrying one dominant and one recessive allele.
A cross between a homozygous recessive and an individual of unknown genotype is called a test cross.The homozygous recessive can only pass on a recessive allele to the offspring, and so any recessive in the other parent will show up in the phenotype (detectable characteristics) of some of the offspring.
A testcross is a genetic cross between an individual with an unknown genotype and a homozygous recessive individual to determine the unknown genotype. This cross helps determine if the individual with the unknown genotype is heterozygous or homozygous for a particular trait.
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most likely to be 50% it makes more sense, you can also get 75%.
If you cross wwgg x WwGg, each parent contributes one allele for the traits. The genotype for wrinkled (w) and green (g) seeds is wwgg, and the genotype for WwGg is heterozygous for smooth and yellow. Therefore, 0% of the offspring will be wrinkled green.
A genetic test cross is helpful in determining the genotype of an individual with unknown genotype by crossing it with a homozygous recessive individual. This allows the alleles to separate and be observed in the offspring, providing information on the genotype of the individual being tested.
there is a 50% chance that the offspring will be tall.
A monohybrid cross between two heterozygous parents (Aa x Aa) would produce 100% heterozygous offspring. Each parent contributes one allele for the trait, resulting in all offspring being heterozygous.
The hybrid is the offspring so the probability is 1.
To identify the P genotype through a genetic cross, you would need to perform a test cross where you mate the individual with an unknown genotype with a homozygous recessive individual. By analyzing the offspring of this cross, you can determine the genotype of the individual in question based on the observed phenotypes of the offspring.