volume/(1/3*pi*(R1^2+R1*R2+R2^2))=height
The formula for the volume of a truncated square pyramid with height h, and top edge a cm and bottom edge b cm is V = 1/3*(a2 + ab + b2)*h.
Yes, but there are different formulae for its surface area, volume, height etc and the exact form of these will also depend on the information that is available.
m= (pieD + pied)/2 x height x thickness x density(kg/m^3)
To calculate the surface area of a truncated pyramid, you first take the surface area of each side. That would be the base time the straight height. If it is a 4 side pyramid with equivelant sides, multiply that answer by 4.
Density = Mass/[(1/3*pi*h) * (R12 + R22 + R1*R2)] where h is the height of the frustum, and R1 and R2 are the radii of the two circular sections.
The formula for calculating development surface area of a truncated cone is Avr = π [s (R + r) + R^2 + r^2]. The solution is area (A) subscript r where r is the radius of the top of the truncated cone. In this formula R stands for the radius of the bottom of the cone and s represents the slant height of the cone.
For a circular cone: sqrt( (R-r)^2 + h^2) where: R = radius of larger end r = radius of smaller end h = height of truncated cone For cones of other shapes the average of the area of the top and bottom surfaces times the height (perpendicular to the plane of the top/bottom)
The formula for the volume of a truncated square pyramid with height h, and top edge a cm and bottom edge b cm is V = 1/3*(a2 + ab + b2)*h.
sqrt( (R-r)^2 + h^2)where:R = radius of larger endr = radius of smaller endh = height of truncated cone
V = (1/3*Pi*h) * (R12 + R22 + R1*R2) Where R1 and R2 are the radii of the bases, and h is equal to the height of the truncated cone.
Yes, but there are different formulae for its surface area, volume, height etc and the exact form of these will also depend on the information that is available.
m= (pieD + pied)/2 x height x thickness x density(kg/m^3)
To calculate the surface area of a truncated pyramid, you first take the surface area of each side. That would be the base time the straight height. If it is a 4 side pyramid with equivelant sides, multiply that answer by 4.
the formula for the AREA of a trapeziem is 1/2(a+b)h a=top side b=bottom side h=height its a good formula but heres a easier one 1/2*(Area of top + Area of bottom)*Height
the formula for the area of a square or rectangle is length times height the formula for the area of a circle is pi times radius squared the formula for the area of a triangle is half base times height the formula for the area of a trapezoid is 1/2(top + bottom) times height
Density = Mass/[(1/3*pi*h) * (R12 + R22 + R1*R2)] where h is the height of the frustum, and R1 and R2 are the radii of the two circular sections.
Base x Height Remember: Height = The line which extends from the top to the bottom of the shape where the line meets the base at 90 degrees