A geometric sequence with 5 terms can alternate by having positive and negative terms. For example, one such sequence could be (2, -6, 18, -54, 162). Here, the first term is (2) and the common ratio is (-3), leading to alternating signs while maintaining the geometric property.
No. Although the ratios of the terms in the Fibonacci sequence do approach a constant, phi, in order for the Fibonacci sequence to be a geometric sequence the ratio of ALL of the terms has to be a constant, not just approaching one. A simple counterexample to show that this is not true is to notice that 1/1 is not equal to 2/1, nor is 3/2, 5/3, 8/5...
1 to 4
You mean what IS a geometric sequence? It's when the ratio of the terms is constant, meaning: 1, 2, 4, 8, 16... The ratio of one term to the term directly following it is always 1:2, or .5. So like, instead of an arithmetic sequence, where you're adding a specific amount each time, in a geometric sequence, you're multiplying by that term.
The numbers 2, 4, 7, 11 are neither strictly arithmetic nor geometric. In an arithmetic sequence, the difference between consecutive terms is constant, while in a geometric sequence, the ratio between consecutive terms is constant. Here, the differences between terms are 2, 3, and 4, suggesting a pattern of increasing increments. Following this pattern, the next two terms would be 16 (11 + 5) and 22 (16 + 6).
The given geometric sequence is 1, 4, 16, where the first term ( a = 1 ) and the common ratio ( r = 4 ). To find the sum of the first six terms, we calculate the sixth term: ( a_6 = a \cdot r^{5} = 1 \cdot 4^5 = 1024 ). The sum of the first ( n ) terms of a geometric sequence is given by the formula ( S_n = a \frac{r^n - 1}{r - 1} ). Thus, the sum of the first six terms is ( S_6 = 1 \cdot \frac{4^6 - 1}{4 - 1} = \frac{4096 - 1}{3} = \frac{4095}{3} = 1365 ).
They are 14, 42, 126, 378 and 1134.
No. Although the ratios of the terms in the Fibonacci sequence do approach a constant, phi, in order for the Fibonacci sequence to be a geometric sequence the ratio of ALL of the terms has to be a constant, not just approaching one. A simple counterexample to show that this is not true is to notice that 1/1 is not equal to 2/1, nor is 3/2, 5/3, 8/5...
1 to 4
The sequence 2, 3, 5, 8, 12 is neither arithmetic nor geometric. In an arithmetic sequence, the difference between consecutive terms is constant, while in a geometric sequence, the ratio between consecutive terms is constant. In this sequence, there is no constant difference or ratio between consecutive terms, so it does not fit the criteria for either type of sequence.
You mean what IS a geometric sequence? It's when the ratio of the terms is constant, meaning: 1, 2, 4, 8, 16... The ratio of one term to the term directly following it is always 1:2, or .5. So like, instead of an arithmetic sequence, where you're adding a specific amount each time, in a geometric sequence, you're multiplying by that term.
No, it is not.
An example of an infinite geometric sequence is 3, 5, 7, 9, ..., the three dots represent that the number goes on forever.
It is 0.2
Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5
Sequences are a group of numbers that follow a certain pattern. There are two kinds of sequences, the arithematic sequence and geometric sequence. Arithematic sequence follows through addition (and subtraction). Geometric sequence follows throug multiplication (and division). Arithematic Sequence Example : 1, 6, 11, 16, 21 The pattern follows an addition of 5. Geometric Sequence Example : 1, 3, 9, 27, 81 The pattern follows a multiplication of 3
a = -4 r = -3
1.25 Apex