Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5
11.27357
A sequence is geometric if each term is found by mutiplying the previous term by a certain number (known as the common ratio). 2,4,8,16, --> here the common ratio is 2.
The common ratio.
This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by 10.
The geometric sequence with three terms with a sum of nine and the sum to infinity of 8 is -9,-18, and 36. The first term is -9 and the common ratio is -2.
the answer is 4
A single number does not constitute a sequence.
To find the 6th term of a geometric sequence, you need the first term and the common ratio. The formula for the nth term in a geometric sequence is given by ( a_n = a_1 \cdot r^{(n-1)} ), where ( a_1 ) is the first term, ( r ) is the common ratio, and ( n ) is the term number. Please provide the first term and common ratio so I can calculate the 6th term for you.
A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio. For example, in the sequence 2, 6, 18, 54, the common ratio is 3. The general form of a geometric sequence can be expressed as ( a_n = a_1 \cdot r^{(n-1)} ), where ( a_1 ) is the first term, ( r ) is the common ratio, and ( n ) is the term number.
36
-1,024
11.27357
It is 1062882.
A single number does not constitute a sequence.
You start with the number 4, then multiply with the "common ratio" to get the next term. That, in turn, is multiplied by the common ratio to get the next term, etc.
The ratio is 4.
Not sure about this question. But, a geometric sequence is a sequence of numbers such that the ratio of any two consecutive numbers is a constant, known as the "common ratio". A geometric sequence consists of a set of numbers of the form a, ar, ar2, ar3, ... arn, ... where r is the common ratio.