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The given geometric sequence is 1, 4, 16, where the first term ( a = 1 ) and the common ratio ( r = 4 ). To find the sum of the first six terms, we calculate the sixth term: ( a_6 = a \cdot r^{5} = 1 \cdot 4^5 = 1024 ). The sum of the first ( n ) terms of a geometric sequence is given by the formula ( S_n = a \frac{r^n - 1}{r - 1} ). Thus, the sum of the first six terms is ( S_6 = 1 \cdot \frac{4^6 - 1}{4 - 1} = \frac{4096 - 1}{3} = \frac{4095}{3} = 1365 ).

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1w ago

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