The object is accelerating
That the object being studied is accelerating in the radial direction.
If you are analyzing speed with respect to time, then you are decelerating.
It means that as time goes on, the distance increases quickly.
The graph of y > - x is an area, firstly draw the line y = -x which is a line sloping diagonally upwards to the left at 45o and the area where y > -x is the area above the line
A horizontal line on a speed vs time graph indicates constant speed.
That the object being studied is accelerating in the radial direction.
If you are analyzing speed with respect to time, then you are decelerating.
It means that as time goes on, the distance increases quickly.
If the graph is a straight line through the origin, sloping upwards to the right, then it is a proportional linear relationship.
The graph of y > - x is an area, firstly draw the line y = -x which is a line sloping diagonally upwards to the left at 45o and the area where y > -x is the area above the line
On a graph of acceleration vs. time, during deceleration the line is below zero. On a graph of speed vs. time, during deceleration the line has a negative slope (sloping downward from left to right).
When there is a curved line going upwards on a graph it means the distance is increasing
An Upward Sloping Straight Line. <3
it depends on what the graph is. if it is a distance vs time graph, the line will be a line with the slope being the speed/total time if it is a speed vs. time graph, the line will be horizontal at y=the speed if it is an acceleration vs time graph, the line will be horizontal at y=0
You can use the steepness, or slope, of a line in a distance-time graph to determine the speed of an object if speed is constant. The slope of the line is calculated by dividing the change in distance by the change in time for that time interval.
Slowing down or decelerating
a steep upward sloping line