There is no specific interval, especially if you define a decrease as a negative increase.
That's the description of the interval. It means that "g" is between the numbers specified.
Open interval does not include its end points while closed interval includes
An interval is the spacing of time. For example: I ran for an interval of 10 minutes then walked for an interval of 30 minutes. Or each car has an interval of 0.5 seconds.
There is no interval in a single number.
There is no specific interval, especially if you define a decrease as a negative increase.
That's the description of the interval. It means that "g" is between the numbers specified.
The range of a negative number is the infinite interval, x < 0.
f(x) is decreasing on the interval on which f'(x) is negative. So we want: (x2-2)/x<0 For this to be true either the numerator or the denominator (but not both) must be negative. On the interval x>0, the numerator is negative for 0<x<sqrt(2) and the denominator is positive for all x>0. On the interval x<0, the denominator is negative for all values on this interval. The numerator is positive on this interval for x<-sqrt(2). So, f' is negative (and f is decreasing) on the intervals: (-infinity, -sqrt(2)), (0, sqrt(2))
false
(-3, 5] = {x : -3 < x ≤ 5}
53
normal interval, close interval, and double interval
The three interval choices are normal interval, close interval and double interval. When forming a squad these are the choices to ensure they are at the correct interval.
Positive: (0, infinity)Nonnegative: [0, infinity)Negative: (-infinity, 0)Nonpositive (-infinity, 0]
No, it's only the acceleration. By (-)ve acceleration ,it means retardation or deceleration..
No, it's only the acceleration. By (-)ve acceleration ,it means retardation or deceleration..