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It is an irrational number such as sqrt(2), pi, e. There are, in fact infinitely more Irrational Numbers than rational ones.

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Q: What is a real life situation for non repeating decimal?
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Related questions

Real life situation for changing repeating decimals into fractions?

there are None!


Is a repeating decimal a real number?

Yes.


Does every repeating decimal correspond to a point on a real number line?

real number


A repeating decimal is a real number?

Yes repeating decimals are real numbers. They can fall under the category of rational numbers under real numbers since their repeating decimal patterns allows them to be converted into a fraction. Nonreal numbers are imaginary numbers which are expressed with i, or sqrt(-1).


What does it mean when you have the same dream again?

Recurring dreams often point toward a problem that has not been resolved in real life. When the real situation is managed, the dream will stop repeating.


What real number is nonterminating and a nonrepeating decimal?

The only real number that is non-terminating and non-repeating is Pi (pie)


How many kilometres makes one mile?

1.6 is close, the real # is a repeating decimal that starts with 1.6


What is the name of A Repeating Number?

A repeating decimal is sometimes called a recurring decimal. The main idea is that at some point it must become periodic. That is to say, a certain part of the decimal must repeat, even though not all of it repeats. The parts that repeats is called the repetend. One very important idea is the a real number has a repeating decimal representation if and only if it is rational.


What about a real life situation to explain why a negative times a negative number will give a positive number?

there is no real life situation


Why is the sqrt of 7 irrational?

It is a non-repeating, non-terminating decimal. That's the definition of an irrational number.


How can we apply a real life situation to a inequality?

real situation example for x=14>17


What is a counterexample to show that the repeating decimals are closed under subtraction false?

In fact, the statement is true. Consequently, there is not a proper counterexample. The fallacy is in asserting that a terminating decimal is not a repeating decimal. First, there is the trivial argument that any terminating decimal can be written with a repeating string of trailing zeros. But, Cantor or Dedekind (I can't remember which) proved that any terminating decimal can also be expressed as a repeating decimal. For example, 2.35 can be written as 2.3499... Or 150,000 as 149,999.99... Thus, a terminating decimal becomes a recurring decimal. As a consequence, all real numbers can be expressed as infinite decimals. And that proves closure under addition.