A number can't be cubed and prime. Cubed numbers (other than 1) have more than two factors.
The sum of the first 100 cubed numbers is 25,502,500.
No. The list of cubed numbers is infinitely long and so it is not possible to generate it.
The sum of the first n cubed numbers is the square of the nth triangular number.
Numbers multiplied by it's self 3 times
2,628,071 and 2,628,073. 138 cubed is 2,628,072
The sum of the first n cubed numbers is: [n*(n+1)/2]2 which is the same as the square of the sum of the first n numbers.
8 is 2 cubed 27 is 3 cubed
The first 5 cubed numbers are 1x1x1=1, 2x2x2=8, 3x3x3=27, 4x4x4=64 and 5x5x5=125. :)
If you mean the sum of two cubed numbers then the answer is simply 'none' with the trivial exception of all of them being 0. For more info check out "Fermat's last theorem".