Perfect cubes.
A number can't be cubed and prime. Cubed numbers (other than 1) have more than two factors.
Well, honey, the cubed numbers between 2000 and 3000 are 8 cubed (512), 9 cubed (729), 10 cubed (1000), 11 cubed (1331), 12 cubed (1728), 13 cubed (2197), 14 cubed (2744), and 15 cubed (3375). So, there you have it, sweetie!
The sum of the first n cubed numbers is the square of the nth triangular number.
The cubed numbers between 50 and 100 are 64 and 81. Specifically, 4 cubed equals 64 (4³ = 64) and 5 cubed equals 125, which exceeds 100. Therefore, the only cubed number in that range is 64.
The sum of the first n cubed numbers is: [n*(n+1)/2]2 which is the same as the square of the sum of the first n numbers.
Numbers multiplied by it's self 3 times
2,628,071 and 2,628,073. 138 cubed is 2,628,072
1, 8, 27, 64
8 is 2 cubed 27 is 3 cubed
The third cubed number is (3^3), which equals (27). Cubed numbers are obtained by raising a number to the power of three, so the first few cubed numbers are (1^3 = 1), (2^3 = 8), and (3^3 = 27). Thus, the third cubed number is 27.
If you mean the sum of two cubed numbers then the answer is simply 'none' with the trivial exception of all of them being 0. For more info check out "Fermat's last theorem".
The first 5 cubed numbers are 1x1x1=1, 2x2x2=8, 3x3x3=27, 4x4x4=64 and 5x5x5=125. :)