6
Wiki User
∙ 11y agoNo. There is no whole number you can multiply 6 by to get 3 (3/6 is 1/2 which isn't a whole number).
If the sum of the digits is a multiple of three, the whole number is a multiple of three.
No, 28 could not be a multiple of 3.No. 28 divided by three is not a whole number, so it is not a multiple of three.
Because when you divide 3 into 103 the answer is not a whole number.
Three is not a multiple of 6 because you can't multiply 6 by a whole number and get the answer 3.
If the digits of the number add up to a multiple of 3, the whole number is divisible by 3.
Divide it by 3, and if its a whole number with no .'s then it's a multiple of 3. 3x=3269283 x=1089761 3269283 is a multiple of 3
Do the division, 617 / 3. If you get a whole number, it's a multiple; otherwise it isn't.
If the number is even, it's divisible by 2. If the sum of the digits is a multiple of 3, the whole number is divisible by 3. If the last two digits are a multiple of 4, the whole number is divisible by 4. If the last digit is a 0 or a 5, the whole number is divisible by 5. If the number is even and divisible by 3, it's divisible by 6. If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7. If the last three digits are a multiple of 8, the whole number is divisible by 8. If the sum of the digits is a multiple of 9, the whole number is divisible by 9. If the number ends in 0, it's divisible by 10.
11
It has to be a whole number, or else every number would be a multiple of every other number.
If the number is even, it's divisible by 2. If the sum of the digits is a multiple of 3, the whole number is divisible by 3. If the last two digits are a multiple of 4, the whole number is divisible by 4. If the last digit is a 0 or a 5, the whole number is divisible by 5. If the number is even and divisible by 3, it's divisible by 6. If the sum of the digits is a multiple of 9, the whole number is divisible by 9. If the number ends in 0, it's divisible by 10.