Y=3x-3
A linear equation is similar to a linear graph in that key data from the equation is clearly visible on the graph. A linear equation of y = 4x + 5 shows us that the y-intercept (or "b") is +5. This is where our line crosses the y-axis, and provides us with the information that the point (0, 5) exists on our line, making it the easiest point to draw on our graph every time! The equation also shows us that there is a slope (or "m") of 4. This means we must do the long-form of slope, which is "rise over run" or "change in y, divided by change in x". A slope of 4 is written as 4/1, or "four over one", showing we 'rise' 4 units on our graph, and 'run' 1 unit...clearly showing a slope of 4.
Slope: * rise over run * if a point on the graph is (2,1) and the slope is 4/3 and you are asked to draw the next point, you would put your pencil on your point, go up four spaces and over 3. The next point would be (6,4) Y-Intercept * point on the graph when the line crosses the y-axis
You have to get your equation into slope intercept form. Slope intercept form is y=mx+b Now use algebra on your equation to get "y" on the left side and "x" and the numbers on the right side.. 2y = 5 - 8x y = -(8/2)x + (5/2) y = -4x + 2.5 Now it is slope intercept form. In the previous y=mx+b equation your m=slope Therefore in your equation m=-4 so your slope is -4/1 This means it go down four units and left one unit. This is rise over run.
-4/3
Put the equation into y=mx+b form.-8x + 6y = 06y = 8xy = 8x/6y= (4/3)xThe slope is four-thirds.
You solve this type of problem using the following steps. 1) Write your original equation in slope-intercept form, that is, solved for "y". (The line is already in that form in this case). You can read off the slope directly: in an equation of the form: y = mx + b m is the slope. 2) Calculate the slope of the perpendicular line. Since the product of the slopes of perpendicular lines is -1, you can divide -1 by the slope you got in part (1). 3) Use the generic equation y - y1 = m(x - x1), for a line that has a given slope "m" and passes through point (x1, y1). Replace the given coordinates (variables x1 and y1). Simplify the resulting equation, if required.
m = - 5 (-4,9) Point slope form. Y - Y1 = m(X - X1) Y - 9 = - 5{X - (-4)} Y - 9 = -5(X + 4) Y - 9 = -5X - 20 y = -5X - 11 ----------------
A linear equation is similar to a linear graph in that key data from the equation is clearly visible on the graph. A linear equation of y = 4x + 5 shows us that the y-intercept (or "b") is +5. This is where our line crosses the y-axis, and provides us with the information that the point (0, 5) exists on our line, making it the easiest point to draw on our graph every time! The equation also shows us that there is a slope (or "m") of 4. This means we must do the long-form of slope, which is "rise over run" or "change in y, divided by change in x". A slope of 4 is written as 4/1, or "four over one", showing we 'rise' 4 units on our graph, and 'run' 1 unit...clearly showing a slope of 4.
slope intercept formula is given by y = mx+c where m is the slope and c is the x intercept so ur equation comes to... y=(0.25)x + 24
Slope: * rise over run * if a point on the graph is (2,1) and the slope is 4/3 and you are asked to draw the next point, you would put your pencil on your point, go up four spaces and over 3. The next point would be (6,4) Y-Intercept * point on the graph when the line crosses the y-axis
You have to get your equation into slope intercept form. Slope intercept form is y=mx+b Now use algebra on your equation to get "y" on the left side and "x" and the numbers on the right side.. 2y = 5 - 8x y = -(8/2)x + (5/2) y = -4x + 2.5 Now it is slope intercept form. In the previous y=mx+b equation your m=slope Therefore in your equation m=-4 so your slope is -4/1 This means it go down four units and left one unit. This is rise over run.
Use the four-step process to find the slope of the tangent line to the graph of the given function at any point.
-4/3
positive slope negative slope zero slope undefined
Put the equation into y=mx+b form.-8x + 6y = 06y = 8xy = 8x/6y= (4/3)xThe slope is four-thirds.
To solve this, four steps are needed:Find the midpoint of the line segment (X, Y) which is a point on the perpendicular bisectorFind the slope m for the line segment: m = change_in_y/change_in_xFind the slope m' of the perpendicular line; the slopes of the lines are related by mm' = -1 → m' = -1/mFind the equation of the perpendicular bisector using the slope-point equation for a line passing through point (X, Y) with slope m': y - Y = m'(x - X)Have a go before reading the solution below.--------------------------------------------------------------------The midpoint of (7, 3) and (-6, 1) is at ((7 + -6)/2, (3 + 1)/2) = (1/2, 2)The slope of the line segment is: m = change_in_y/change_in_x = (1 - 3)/(-6 - 7) = -2/-13 = 2/13The slope of the perpendicular bisector is m' = -1/m = -1/(2/13) = -13/2The equation of the perpendicular bisector passing through point (X, Y) = (1/2, 2) with slope m' = -13/2 is given by:y - Y = m'(x - Y)→ y - 2 = -13/2(x - 1/2)→ 4y - 8 = -26x + 13→ 4y + 26x = 21
1. Given 2. Find 3. Equation 4. Solution