You solve this type of problem using the following steps.
1) Write your original equation in slope-intercept form, that is, solved for "y". (The line is already in that form in this case). You can read off the slope directly: in an equation of the form:
y = mx + b
m is the slope.
2) Calculate the slope of the perpendicular line. Since the product of the slopes of perpendicular lines is -1, you can divide -1 by the slope you got in part (1).
3) Use the generic equation y - y1 = m(x - x1), for a line that has a given slope "m" and passes through point (x1, y1). Replace the given coordinates (variables x1 and y1). Simplify the resulting equation, if required.
12
Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0
It works out in its general form as: 3x-4y-6 = 0
The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"
y = 1/3x+4/3
negative 1
Find an equati find an equation for the line perpendicular to the line 8x - 8 y equals negative 2 having the same Y intercept as -6x + 2 y equals negative 8
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y=-x
It would be perpendicular to a line with the equation Y = 1/8 X.
8
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0
Perpendicular to 2x - 3y = 8 through the point ( 2, 1 ) (Perpendicular means the slopes are negative inverses of each other) 3x+2y = 8
"Y = any number" is perpendicular to "x = -3".
The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0
No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3