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A rectangle has a width of 12.4 ft and a length of 50 ftwhat is the length of the rectangle?
Wiki User
∙ 9y ago
To answer the question as written: If the length of a rectangle is given as being 50 feet, then the length of the rectangle is 50 feet. To answer the question that is really being asked, if the width of a rectangle is 12.4 feet and the length of 50 feet, the area can be found by multiplying the length by the width. Therefore, the are of the rectangle would be 620 square feet. If however, the question was to determine the perimeter, you would use the formula 2l+2w=p so you would add 12.4 +12.4+50+50, for a perimeter of 124.8 feet.
Wiki User
∙ 9y ago
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A rectangle has an area of 124 cm2 has a length that is 4 times the width how long is the width also-round to the nearest tenth--answer options--5.6cm OR 22.3cm OR 11.1cm and 44.5cm?
124=4wxw 124/4=4w2/4 31=w2 5.56=w L=22.4 W=5.6
How many different rectangles exist which have numbers as the length and width have the area of 36 sqcm?
If you mean whole 'numbers', then here are the rectangles:1 x 362 x 183 x 124 x 96 x 6(That last one is a square, which is a special rectangle.)
What is the side length of a square if the area ia 124?
the square root of 124
Find the length of a rectangular lot with a perimeter of 140 meters if the length is 8 meters more than the width?
Let the length be x+8 and the width be x: 2(x+8)+2x = 140 2x+16+2x = 140 4x+16 = 140 4x = 140-16 4x = 124 x = 31 Therefore: length = 31+8 = 39 meters
The yard is 124 feet long and 62 feet wide. hany many feet of fencing does Melissa need to surround her entire yard?
Find the Perimeter P= 2(length) + 2(width) = 2(124) + 2(62) = 372 ft. of fencing
A rectangle has an area of 124 cm2 has a length that is 4 times the width how long is the width also-round to the nearest tenth--answer options--5.6cm OR 22.3cm OR 11.1cm and 44.5cm?
124=4wxw 124/4=4w2/4 31=w2 5.56=w L=22.4 W=5.6
What is the area of a rectengle 14cm by 12cm?
The area of EVERY rectangle is the product of (length) times (width).Knowing that, you can now find the area of not only that particular rectangle,but also every rectangle you ever encounter for the rest of your life.Man, you are empowered !
How many different rectangles exist which have numbers as the length and width have the area of 36 sqcm?
If you mean whole 'numbers', then here are the rectangles:1 x 362 x 183 x 124 x 96 x 6(That last one is a square, which is a special rectangle.)
The perimeter of a rectangle is 124 inches the length exceeds the width by 28 inches find the length and the width?
Here is what we are given:1. 2L + 2W = 1842. L = W + 32Since we know L in terms of W, we can substitute equation (2) into equation (1), and solve for W:3. 2(W+32) + 2W = 1844. 2W + 64 + 2W = 1845. 4W + 64 = 1846. 4W = 1207. W = 30Now we know the width, substitute this back into equation (2):8. L = 30+ 329. L = 62Now check the result by substituting these values into equation (1):10. 2(62) + 2(30) = 18411. 124 + 60 = 18412. 184 = 184QED
What is the side length of a square if the area ia 124?
the square root of 124
Find the length of a rectangular lot with a perimeter of 140 meters if the length is 8 meters more than the width?
Let the length be x+8 and the width be x: 2(x+8)+2x = 140 2x+16+2x = 140 4x+16 = 140 4x = 140-16 4x = 124 x = 31 Therefore: length = 31+8 = 39 meters
What is the perimeter of a rectangle if the area is 120?
The answer is indeterminate, because there are many different rectangles, with different perimeters, whose area can equal 120. Some examples (area being length X width, and perimeter being 2 X length + 2 X width): * Where L=20 & W=6, A=120 and P=40+12=52. * Where L=30 & W=4, A=120 and P=60+8=68. * Where L=60 & W=2, A=120 and P=120+4=124.
The yard is 124 feet long and 62 feet wide. hany many feet of fencing does Melissa need to surround her entire yard?
Find the Perimeter P= 2(length) + 2(width) = 2(124) + 2(62) = 372 ft. of fencing
What is the perimeter of a rectangle that is 40 inches long and 22 inches wide?
124 inches
27.8 meters by 34.2 meters What is the perimeter?
Assuming the figure is a regular rectangle, the perimeter of the rectangle will be (27.8 + 34.2) x 2 = 124 centimetres.
What is the surface area of a cylinder if the diameter is 124 mm and the length is 170 mm?
A cylinder if the diameter is 124 mm and the length is 170 mm has a surface area of 90,377.34mm2
What are the dimensions if the perimeter is 124 feet and the length is 6 feet more than 3 times the width?
Create an equation to solve the problem. p=2l=2w l=3w+6 the perimeter is 124. We substitute 124 for p and 3w+6 for l to reach the following solvable equation 124=2(3w+6)+2w 124=6w+12+2w (distribute the 2 over 3w+6) 124=8w+12 (combine like terms) 124-12=8w+12-12 (subtract 12 from both sides to isolate the variable w) 112=8w (combine like terms again) 112/8=8w/8 (divide both sides by 8 to isolate w) 14=w We now know the width is 14 feet. We then substitute that value for w in the equation we wrote for the value of l l=3w+6 l=3*14+6 l=42+6 l=48 The length is 48 feet. We can now substitute both values into the equation for perimeter to check our answer. p=2w+2l 124=(2*14)+(2*48) 124=28+96 124=124 The result is true, so the result is correct.
