It is not possible to add up an even and uneven number to attain ten, or any other even number.
Consider the following a proof:
a is a even number
b is a uneven number, this means that (b-1) is a even number.
a+b = a + (b-1) + 1
2 even numbers added up always result in an even number. And each time, 1 gets added to that sum, netting a uneven number.
Ten Is An Even Number.
That's impossible. Adding up an odd number of odd numbers will give an answer that is an odd number. 50 is an even number. So adding up 5(5 is an odd number) odd numbers will not give 50, an even number.
Even. If it can be rationed out evenly between two people, it is even, if it can't the number is odd.
even
No. 10 - 2 = 8. The number 8 is even, not odd.
To do front end rounding with odd numbers, you round up to the nearest even number. For example, if you have the odd number 7 and you want to do front end rounding to the nearest ten, you round up to the nearest even ten, which is 10.
I don't see how this can be done, because when any two odd numbers are added together, the sum is even. If the first two cups each have an odd number the remainder will be 10 - (an even number). Any even number - an even number will equal an even number. Therefore this is not possible.
odd
Just look at the last digit. If it's even, then the number is even. If it's odd, then the number is odd. (The other digits tell you how many tens, hundreds, etc. Ten, or a multiple of ten - like seventy or eighty - is always even. Same goes for hundreds, thousands, etc.)
There are no numbers between 108 and 120 that have an even ten's digit. If you call 'zero' an even number, then ' 109 ' would qualify. But the whole exercise is still not too satisfying.
0 is the ten's digit of the first odd number.
Ten