It is not possible to add up an even and uneven number to attain ten, or any other even number.
Consider the following a proof:
a is a even number
b is a uneven number, this means that (b-1) is a even number.
a+b = a + (b-1) + 1
2 even numbers added up always result in an even number. And each time, 1 gets added to that sum, netting a uneven number.
Ten Is An Even Number.
That's impossible. Adding up an odd number of odd numbers will give an answer that is an odd number. 50 is an even number. So adding up 5(5 is an odd number) odd numbers will not give 50, an even number.
Even. If it can be rationed out evenly between two people, it is even, if it can't the number is odd.
Odd - the last ten digits of Graham's number are ...2464195387.
No. 10 - 2 = 8. The number 8 is even, not odd.
I don't see how this can be done, because when any two odd numbers are added together, the sum is even. If the first two cups each have an odd number the remainder will be 10 - (an even number). Any even number - an even number will equal an even number. Therefore this is not possible.
Just look at the last digit. If it's even, then the number is even. If it's odd, then the number is odd. (The other digits tell you how many tens, hundreds, etc. Ten, or a multiple of ten - like seventy or eighty - is always even. Same goes for hundreds, thousands, etc.)
The only factor of 100 that is greater than ten and odd is 25.
A decimal number is simply a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right. A decimal representation does not require a decimal point. If it is a decimal representation of an integer, then it can be either even or odd..
Only perfect squares can have an odd number of factors. The answer is 16. It has five factors: 1,2,4,8,16.
There are no numbers between 108 and 120 that have an even ten's digit. If you call 'zero' an even number, then ' 109 ' would qualify. But the whole exercise is still not too satisfying.
when you add a number from 3 to 9
Ten is an even integer.
1000001 is the smallest 7 digit odd number...
You can work this out pretty quick; just assemble the number in parts. We know the number must be odd, so the last digit has to be an odd one. Let's make it three: 3 Now we need to add five more digits that collectively add up to seven (giving us the sum of ten for our six digits. There's no limit of repetition limit, so we can simply say our numbers are 1, 1, 1, 2 and 2: 111223 That's our last six digits that add up to ten. To get four different eight-digit odd numbers, all we have to do is add four combinations of two digits on the beginning: 99111223 98111223 97111223 96111223
one to ten
The smallest odd 7-digit number is 1,000,001 .If you also want the ones digit to be the sum of the thousands and ten-thousands digits,then the smallest odd 7-digit number that satisfies that additional requirement is 1,001,001,but it's no longer the smallest odd 7-digit number.
Just add them together, and divide the result by 10. (For the average of a larger set of consecutive odd numbers, it's faster to use the formula for an arithmetic series to add them up. Also, the average of such a set is the same as if you just average the first and the last number.)
My number is 11.
9 is an odd square number less than 10 and 92 = 81 which is greater than 50