I don't see how this can be done, because when any two odd numbers are added together, the sum is even. If the first two cups each have an odd number the remainder will be 10 - (an even number). Any even number - an even number will equal an even number. Therefore this is not possible.
If there are 20 red marbles and 40 blue marbles, the ratio of red to blue is 1 over 2. The number of white marbles does not matter.
The theoretical probability of randomly picking each color marble is the number of color marbles you have for each color, divided by the total number of marbles. For example, the probability of selecting a red marble is 3/20.
Set up the problem as: y=number of yellow marbles & 4y=number of blue marbles. 40=y+4y or 40=5y or y=8. Therefore number of blue marbles is 4*8 = 32.
The number of marbles left in a 48 marble bag after some number N marbles have been given away is 48-N.
This problem doesn't lead to a whole number solution. Are you sure you copied it correctly? Maybe you meant the ratio is 4 to 3. In that case: red/blue = 4/3 blue/red = 3/4 blue = (3 * red) / 4 = (3 * 16) / 4 = 12 blue marbles
put one cup into another cup, then put 5 marbles in each.
If there are 20 red marbles and 40 blue marbles, the ratio of red to blue is 1 over 2. The number of white marbles does not matter.
Four. The answer will be 12 to 6 which reduced is 2 to 1.
4 in each bag. 2*4 = 8 bags 8 bags of 4 marbles = 32 marbles
The theoretical probability of randomly picking each color marble is the number of color marbles you have for each color, divided by the total number of marbles. For example, the probability of selecting a red marble is 3/20.
He has a number of yellow marbles that leaves a reminder of 2 when divided by 3 and is a number smaller than 22. That is the number of yellow marbles = 2(mod 3).
Let X = the number of green marbles. X+3 = the number of blue marbles. X + (X+3) = 23 2X + 3 = 23 2X = 20 X = 10 or the number of green marbles.
Set up the problem as: y=number of yellow marbles & 4y=number of blue marbles. 40=y+4y or 40=5y or y=8. Therefore number of blue marbles is 4*8 = 32.
Number of marbles in total = 90 Fraction of marbles are blue = five-ninth Number of blue marbles = five-ninth of ninety = 50 So, the answer is 50 blue marbles.
Number of different possible choices = 8 + 6 + 9 = 23Number of available successful choices (blue marbles) = 6Probability of success = 6/23 = 0.26087 = 26.087 %(rounded)
The number of marbles left in a 48 marble bag after some number N marbles have been given away is 48-N.
This problem doesn't lead to a whole number solution. Are you sure you copied it correctly? Maybe you meant the ratio is 4 to 3. In that case: red/blue = 4/3 blue/red = 3/4 blue = (3 * red) / 4 = (3 * 16) / 4 = 12 blue marbles