Total surface area = 2*(L*B + B*H + H*L) square units where L = length, B = breadth and H = height.
length *width*height=area of cuboid
derivation of surface area of cuboid
A cuboid is a 3 dimensional object and 3 measures are required for the total surface area of a cuboid.
Volume of a cuboid = cross-section area times its length
Lateral surface area of a cuboid = 2 (Length + Breadth) × Height Lateral surface area of a cube = 4 × Side2
A cuboid is a hexahedron. That is a solid face with six faces. More specifically, all six faces of a cuboid are rectangular. The total surface area of a cuboid with sides of length A, B and C is 2*(AB + BC + CA) sq units.
The surface area of a cuboid can be calculated using the formula (2(ab + ac + bc)), where (a), (b), and (c) are the dimensions of the cuboid. For a cuboid with dimensions 1, 2, and 3, the surface area is (2(1 \cdot 2 + 1 \cdot 3 + 2 \cdot 3) = 2(2 + 3 + 6) = 2 \times 11 = 22) square units. Therefore, the surface area of the 1x2x3 cuboid is 22 square units.
It depends on whether they are stuck together so as to form a 1x1x6 cuboid or a 1x2x3 cuboid, or a 1x1x2 cuboid on top of a 1x2x2 cuboid. Each of these will give a different answer.
2[l+w+h]
Surface area of cuboid = 2*[L*B + B*H + H*L] where L = length, B = breadth, and H = height
The total surface area of a cuboid with edges of length a, b and c units is 2*(ab + bc + ca) square units.
With great difficulty because more information about the dimensions of the cuboid are required.