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Logarithmic equation
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what is the equation
"Figure out this mathematical equation" "This is how to figure out an equation" "An equation is something widely used in mathematics."
It is the solution to the equation or a root of the equation.
deltaG = deltaH -TdeltaS. deltaG = 0 at equilibrium. Therefore deltaH = TdeltaS
NaBH4 + 2H2O -> NaBO2 + 4H2 [1] DeltaG(298K)= -299 kJ/mol BH4 DeltaH(298K)= -231 kJ/mol BH4 (10.8 mass% H) NaBH4 + 4H2O -> NaB(OH)4 + 4H2 [2] DeltaG (298K)= -315 kJ/mol BH4 DeltaH = -247 kJ/mol BH4 (7.28 mass% H) NaBH4 + 6H2O -> NaB(OH)4.2H2O [3] DeltaG = -319kJ/mol BH4 DeltaH = -213 kJ/mol BH4 (5.48 mass% H) *Hydrolysis in Eq.[1] is not the most favorable reaction!
DeltaG = DeltaH - TDeltaS dG = -54.32 kJ/mol - (54'32+273)K(-354.2J/molK) NB Thevtemperature is quoted in Kelvin(K) and the Entropy must be converted to kJ by dividing by '1000'/ Hence dG = - 54.32kJ/mol - (327.32K)(-0.3542 kJ/molK) NB The 'K' cancels out. Then maker the multiplication dG = -54/32 kJ/mol - - 115.94 kJ/mol Note the double minus; it becomes plus(+). Hence dG = -54.32kj/mol + 115.94 kJ/mol dG = (+)61.61 kJ/mol Since dG is positive, the reaction is NOT thermodynamically feasible.
the reaction is exothermic
A thermochemical equation shows the amount of heat given out or taken in when the reaction occurs. CH4 + 2O2 = CO2 +2H2O, deltaH = -890 kJ/mol Note delta H is negative when heat is given out, exothermic and +ve when endothermic. Sorry can't do delta symbol - its a triangle!
Dry ice evaporating is endothermic-->+DeltaH A sparkler burning is exothermic--->-DeltaH The reaction that occurs in a chemical cold pack often used to ice athletic injuries is endothermic--->+DeltaH
-830
•deltaG = nFE • •Pt + In3+ > In + Pt2+ •Pt > Pt2+ + 2e- •In3+ +3e- > In
A thermochemical equation shows the amount of heat given out or taken in when the reaction occurs. CH4 + 2O2 = CO2 +2H2O, deltaH = -890 kJ/mol Note delta H is negative when heat is given out, exothermic and +ve when endothermic. Sorry can't do delta symbol - its a triangle!
The change in enthalpy between products and reactants in a reaction
Enthalpies from reaction steps are added to determine an unknownHreaction.
The Nernst equation is E = ((-2.3RT)/zF)*(log10 [Ci/Co])E = equilibrium potential (mV)z = charge on the ion(2.3RT)/F = constant (60mV at 37C)Ci = intracellular concentrationCo = extracellular concentrationThe Nernst equation is important because it shows what the equilibrium potential would be for one ion.E.g. The resting membrane potential is normally ~70mV. So during an action potential Na channels open their gates briefly and Na rush inside the cell. Na is ionized and carries a positive charge. So when Na rushes into the cell it makes the inside of the cell more positive. If you were to break off the gate and allow Na to move freely back and forth, the Nernst equation shows us that the equilibrium point for Na is ~+65mV.•deltaG - DG0 = R T ln Q• deltaG = nFE••••E = E0+ (RT / nF) ln Q