All multiples of 95, which is an infinite number.
1, 5, 19, 95 There are an infinite amount of numbers divisible by 95
95 is divisible by 5, so no, it is not
They are both divisible by 1 and 19.
No.
No.
No - 95/3 = 31.6 recurring (that is, 31.6666..)
1, 5, 19, 95
yes, 95
No, it is not.
95 95/5=19
Actually, 95 is not a prime number because it is divisible by 5.
No. To be divisible by 9 the sum of the digits must also be divisible by 9. As the sum must be divisible by 9, the check can also be applied to the sum; so keep summing until a single digit remains, then if, and only if, this single digit is 9 is the original number divisible by 9 (the single digit gives the remainder when the original number is divided by 9 and is known as the digital root of the number). For 95: 95 → 9 + 5 = 14 14 → 1 + 4 = 5 5 ≠ 9 → 95 is not divisible by 9. (The remainder when 95 is divided by 9 is 5).