They are both divisible by 1 and 19.
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95 is divisible by 5, so no, it is not
yes, 95
Not evenly. But it is 44.33333 (repeating) or 44 1/3.
Actually, 95 is not a prime number because it is divisible by 5.
No. To be divisible by 9 the sum of the digits must also be divisible by 9. As the sum must be divisible by 9, the check can also be applied to the sum; so keep summing until a single digit remains, then if, and only if, this single digit is 9 is the original number divisible by 9 (the single digit gives the remainder when the original number is divided by 9 and is known as the digital root of the number). For 95: 95 → 9 + 5 = 14 14 → 1 + 4 = 5 5 ≠ 9 → 95 is not divisible by 9. (The remainder when 95 is divided by 9 is 5).