95 is divisible by 5, so no, it is not
Not evenly. But it is 44.33333 (repeating) or 44 1/3.
yes, 95
Actually, 95 is not a prime number because it is divisible by 5.
No. To be divisible by 9 the sum of the digits must also be divisible by 9. As the sum must be divisible by 9, the check can also be applied to the sum; so keep summing until a single digit remains, then if, and only if, this single digit is 9 is the original number divisible by 9 (the single digit gives the remainder when the original number is divided by 9 and is known as the digital root of the number). For 95: 95 → 9 + 5 = 14 14 → 1 + 4 = 5 5 ≠ 9 → 95 is not divisible by 9. (The remainder when 95 is divided by 9 is 5).
133 divided by 7 = 19 so 133 is divisible by 7
No. 133+7 =140 which is divisible by 7, so 133 is also divisible by 7. (It is 7 * 19.)
No.
Yes.
95% of 140 = (140/100)*95 = 133 therefore a 95% inclease of 140 = (133+140) = 273
The GCF (Greatest Common Factor) of 95 and 133 is: 19
1, 5, 19, 95 There are an infinite amount of numbers divisible by 95
567 is divisible by 9. 32 and 133 are not.
665 is divisible by 1, 5, 7, 19, 35, 133, 665.
95 is divisible by 5, so no, it is not
No.
No.