For this, you need the Pythagorean theorem.
Let A equal x + 9
Let C equal 26
A^2 + B^2 = C^2
(x + 9)^2 + B^2 = 26^2
x^2 + 18x + 81 + B^2 = 676
x^2 + 18x + B^2 = 595
This doesn't help you find x, but I hope this did something!
An equal sided triangle cannot have a hypotenuse!
True, because the slant height and the altitude, or height, of the pyramid form one leg and the hypotenuse of a triangle withing the pyramid, and the hypotenuse of a triangle is always the longest side- it is not possible for the hypotenuse to be equal to the legs of a right triangle. (It is a right triangle because an altitude is perpendicular to the base of a pyramid.)
It is the median which divides the side which is not one of the equal sides.
To prove triangle TUX is congruent to triangle DEO by the Hypotenuse-Leg (HL) theorem, we need to establish that both triangles are right triangles. Specifically, we need to confirm that the hypotenuse of triangle TUX is equal to the hypotenuse of triangle DEO, and that one leg of triangle TUX is equal to one leg of triangle DEO. Additionally, we should identify the right angles in both triangles to validate their classification as right triangles.
The square of the hypotenuse is equal to the length of the hypotenuse times itself. This is also equal to the sum of the squares of the other two sides in a right triangle.
No. The altitude is smaller.
Are equal to the square of its hypotenuse.
Its diameter.
It would be an isosceles right triangle. The two sides that aren't the hypotenuse are equal, with lengths of 16.971 (rounded) .
sum of squares of opposite sides
Pythagorean Theorem: In a right triangle, the square on the hypotenuse is equal to the sum of the squares on the other two sides.Converse: If the square on the hypotenuse is equal to the sum of the squares on the other two sides of a triangle, then it is a right triangle.
In a right angled triangle its hypotenuse when squared is equal to the sum of its squared sides which is Pythagoras' theorem for a right angle triangle.