cos(-100 degrees)
f(x) = 2 cos 3x The amplitude: A = |2| = 2 The maximum value of the function: 2 The minimum value of the function: -2 The range: [-2, 2]
sin(2x)=(1/2)sin(x)cos(x), so 6sin(x)cos(x)=12sin(2x)
4 sin(6x) cos(6x) is already a function of a single variable. The variable is ' x '.
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
y=3cos(x) peroid is 2pie
An even function is one where f(x) = f(-x) For cosine, cos(x) = cos(-x), thus cosine is an even function.
No, but cos(-x) = cos(x), because the cosine function is an even function.
cos x equals cos -x because cos is an even function. An even function f is such that f(x) = f(-x).
The cosine function is an even function which means that cos(-x) = cos(x). So, if cos of an angle is positive, then the cos of the negative of that angle is positive and if cos of an angle is negative, then the cos of the negative of that angle is negaitive.
False; the cosine function is an even function as cos(-x) = -cos(x).
cos(495) = cos(495-360) = cos(135) = -cos(180-135) = -cos(45) = -sqrt(1/2) or -1/sqrt(2)
Cos(-155) = cos(155) = 1 - cos(180-155) = 1-cos(25).
The answer is cos A . cos A = 1/ (sec A)
0.766
cos x=.091 x=(cos^-1).091 x=84.779
cos 60
Since the range of the cosine function is (-1,1), the function y = cos(x) assumes a minimum value of -1 for y.