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What is the range of a a function f when it is defined by f x 2 cos 3 x where x is a real number?
f(x) = 2 cos 3x The amplitude: A = |2| = 2 The maximum value of the function: 2 The minimum value of the function: -2 The range: [-2, 2]
Express as a single sine or cosine function 6 sin x cos x?
sin(2x)=(1/2)sin(x)cos(x), so 6sin(x)cos(x)=12sin(2x)
How do you write 4sin6xcos6x as a function of a single variable?
4 sin(6x) cos(6x) is already a function of a single variable. The variable is ' x '.
If Sin equals x and Cos equals y then x squared equals what function of y?
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
What is the derivative of 3cosx?
The derivative of 3cos(x) is -3sin(x). This can be found using the chain rule, which states that the derivative of a composition of functions is the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function. In this case, the derivative of cos(x) is -sin(x), and when multiplied by the constant 3, we get -3sin(x) as the derivative of 3cos(x).
