Q: What is the cos of a 40 degree angle?

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This can be done on a graphing calculator by making sure you have your calculator in degrees mode, and then tentering the cos(23). You get an answer of 0.9205048535.

cos(30)cos(55)+sin(30)sin(55)=cos(30-55) = cos(-25)=cos(25) Note: cos(a)=cos(-a) for any angle 'a'. cos(a)cos(b)+sin(a)sin(b)=cos(a-b) for any 'a' and 'b'.

Sorry, but cos(50)sin(40) - cos(40)sin(50) is -0.1736, which is not even close to sin(90) which is 1.This does not work in radians, either. Please restate your question.

A Quadrantal angle is an angle that is not in Quadrant I. Consider angle 120. You want to find cos(120) . 120 lies in quadrant II. Also, 120=180-60. So, it is enough to find cos(60) and put the proper sign. cos(60)=1/2. Cosine is negative in quadrant II, Therefore, cos(120) = -1/2.

Cos is the ratio between adjacent side (of the given angle thieta) to the hypotenuse of the triangle.

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A 40 degree angle is the COMPLEMENT of a 50 degree angle.

Any polygon can have a 40-degree angle. It doesn't have to, but it can.

In degree mode. cos(40) = 0.7660444431 degrees ( 77 degrees will do ) In radians. cos(40) = - 0.6669380617 radians

A 40 degree acute angle can be constructed with a straight edge and a protractor.

cos(50) = 0.6428 (rounded)

A 40 degree angle is an acute angle, since all angles less than 90 are acute.

Fifty degrees. 90+40+90=180

cos 45o = 1/√2 = 1/2 x √2 ≈ 0.707

140o

It is an acute angle.

Cos(65 deg) = 0.4226 approx.

90 - 40 = 50 degrees.