Any number between a googol/10 and a googol minus 1.
10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 - 1 = 999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999
9999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999 is 9.999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999 x 10^99. It is also written as 10^100-1, since it is 9 followed by 99 nines, (A googol is 1 followed by 100 zeroes) it is a googol minus one.
No. These are the 'illion' numbers: Million, billion, trillion, quadrillion, quintillion, sextillion, septillion, octillion, nonillion, decillion, undecillion, duodecillion, googol and googolplex.
9,999,...,985,000,000,000 There are 89 nines at the start of the number.
it is a septillion sextillion1 with 21 zeros septillion1 with 24 zeros octillion1 with 27 zeros googol1 with 100 zeros googolplex1 with a googol of zeros
A googol is 10^100. So a googol times a googol is 10^200.
what is after the sextillions A sextillion is only 10 with 21 zeros after it, there are many more numbers that are more than a sextillion such as septillion, octillion, nonlillion, decillion, etc. A googol, which is 10 to the 100th power, is bigger than a sextillion.
2 googol
googol and one, googol and two, googol and three...
nope. there is no highest number. for if there were, you could add 1 to it and the resulting number would be larger than the previously declared "highest number" named numbers following trillion are quadrillion = 10^15 quintillion = 10^18 sextillion = 10^21 septillion = 10^24 ... ... googol = 10^100 googolplex = 10^googol
There are (googol+1) of them.