Any number between a googol/10 and a googol minus 1.
A googolplex is defined as 10 raised to the power of a googol, which is (10^{10^{100}}). To determine the number of digits in a googolplex, you can use the formula for the number of digits in a number (n), which is given by ( \lfloor \log_{10}(n) \rfloor + 1). Applying this to a googolplex, it has (10^{100} + 1) digits. Thus, a googolplex has (10^{100}) digits, plus one additional digit.
Yes. But that is true only if the 100 digits do not include 0. Or, if 0 is included, then you consider "0n0" to be a three digit number. Most people would consider is to be a 2-digit number.
100 is a 3 digit number.
100 001
82
300
139
A googolplex is defined as 10 raised to the power of a googol, which is (10^{10^{100}}). To determine the number of digits in a googolplex, you can use the formula for the number of digits in a number (n), which is given by ( \lfloor \log_{10}(n) \rfloor + 1). Applying this to a googolplex, it has (10^{100} + 1) digits. Thus, a googolplex has (10^{100}) digits, plus one additional digit.
I am a number less then 100 two of my factors are 3 and 5 my digits are 1 apart
-100 all the way to -999
A googol is one followed by 100 zeros ( 100 digits). That is less than a billion digits, for sure. But a googolplex is one follwed by a googol number of zeros. That is more than a billion digits, for sure.
Yes. But that is true only if the 100 digits do not include 0. Or, if 0 is included, then you consider "0n0" to be a three digit number. Most people would consider is to be a 2-digit number.
The answer depends on which number is missing. It could be any number from 71 to 100.
No. 1000 has 4 digits and is the smallest 4-digit number. The smallest 3-digit number is 100.
100 is a 3 digit number.
100 001
300, 600 and 900.