The largest positive value that can be stored in 20 bits is calculated using the formula for the maximum value of an unsigned binary number, which is (2^n - 1), where (n) is the number of bits. For 20 bits, this is (2^{20} - 1 = 1,048,576 - 1 = 1,048,575). Therefore, the largest positive value that can be stored in 20 bits is 1,048,575.
216 -1
If the 8 bits represent a signed number, the range is usually -128 to +127. This is -27 to 27-1.
The largest possible value using 8 bits in binary is actually quite simple. Binary is a numerical system that only uses 2 numbers (1 and 0) to determine value. Our system is decimal. (0-9) Now, a 'bit' is one number from the binary system. It can either be 1 or 0. So, 8 bits means using 8 digits in binary. 1 is greater than 0, so the largest value is 11111111. (8 'one's)
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
The largest binary number that can be expressed with 16 bits is 1111111111111111, which is equivalent to 65,535 in decimal. This number uses all 16 bits set to 1. In general, for an n-bit binary number, the maximum value is (2^n - 1). Thus, for 16 bits, it is (2^{16} - 1 = 65,535).
216 -1
0xffffffffffffffff As an unsigned 64-bit integer, this represents the value 18,446,744,073,709,551,615. However, as a signed 64-bit integer, this only represents the value -1. The signed range is -9,223,372,036,854,775,808 to 9,223,372,036,854,775,807 making 0x7fffffffffffffff the largest possible positive value, and 0x8000000000000000 the smallest possible negative value.
There are 5 bits in the immediate value for an LC-3 ADD, but the first bit is needed for the sign representation. The answer is 15.
If the 8 bits represent a signed number, the range is usually -128 to +127. This is -27 to 27-1.
255 is the largest decimal number. 1 byte (8 bits) can store 256 *values* (0-255).
Since 8 bits = 1 byte, the maximum value it could have can be found when all 8 bits are "turned on" or are 1's. 1111 1111 = 128 + 64 + 32 + 16 + 8 + 4 + 2 + 1 = 255
The largest possible value using 8 bits in binary is actually quite simple. Binary is a numerical system that only uses 2 numbers (1 and 0) to determine value. Our system is decimal. (0-9) Now, a 'bit' is one number from the binary system. It can either be 1 or 0. So, 8 bits means using 8 digits in binary. 1 is greater than 0, so the largest value is 11111111. (8 'one's)
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
11b which is 1*2 + 1*1 = 3 would be for two bits. But a byte is 8 bits, so 2 bytes is 16 bits. The largest binary number is [2^16 - 1], which is 65535 (base ten)
The largest binary number that can be expressed with 16 bits is 1111111111111111, which is equivalent to 65,535 in decimal. This number uses all 16 bits set to 1. In general, for an n-bit binary number, the maximum value is (2^n - 1). Thus, for 16 bits, it is (2^{16} - 1 = 65,535).
An 8-bit unsigned integer can represent values ranging from 0 to 255. This is because, with 8 bits, there are (2^8 = 256) possible combinations of binary digits. Therefore, the smallest value is 0 (all bits are 0) and the largest value is 255 (all bits are 1).
The largest number of bits a CPU can process is word size. A CPU's Word Size is the largest number of bits the CPU can process in one operation.