216 -1
The largest positive value that can be stored in 20 bits is calculated using the formula for the maximum value of an unsigned binary number, which is (2^n - 1), where (n) is the number of bits. For 20 bits, this is (2^{20} - 1 = 1,048,576 - 1 = 1,048,575). Therefore, the largest positive value that can be stored in 20 bits is 1,048,575.
If the 8 bits represent a signed number, the range is usually -128 to +127. This is -27 to 27-1.
An 8-bit unsigned integer can represent values ranging from 0 to 255. This is because, with 8 bits, there are (2^8 = 256) possible combinations of binary digits. Therefore, the smallest value is 0 (all bits are 0) and the largest value is 255 (all bits are 1).
signed magnitude
There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.
The largest positive value that can be stored in 20 bits is calculated using the formula for the maximum value of an unsigned binary number, which is (2^n - 1), where (n) is the number of bits. For 20 bits, this is (2^{20} - 1 = 1,048,576 - 1 = 1,048,575). Therefore, the largest positive value that can be stored in 20 bits is 1,048,575.
There are 5 bits in the immediate value for an LC-3 ADD, but the first bit is needed for the sign representation. The answer is 15.
If the 8 bits represent a signed number, the range is usually -128 to +127. This is -27 to 27-1.
An 8-bit unsigned integer can represent values ranging from 0 to 255. This is because, with 8 bits, there are (2^8 = 256) possible combinations of binary digits. Therefore, the smallest value is 0 (all bits are 0) and the largest value is 255 (all bits are 1).
0xffffffffffffffff As an unsigned 64-bit integer, this represents the value 18,446,744,073,709,551,615. However, as a signed 64-bit integer, this only represents the value -1. The signed range is -9,223,372,036,854,775,808 to 9,223,372,036,854,775,807 making 0x7fffffffffffffff the largest possible positive value, and 0x8000000000000000 the smallest possible negative value.
how many bits are needed to represent decimal values ranging from 0 to 12,500?
17 bits would allow a value up to 131071.
1111111111111111 (216 - 1 = 65535)
Well, honey, with 6 bits, you can represent numbers from 0 to 63. So, technically speaking, the largest number you can make with 6 bits is 63. Don't go expecting any bigger miracles with just 6 bits, darling.
signed magnitude
There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.
The largest possible value using 8 bits in binary is actually quite simple. Binary is a numerical system that only uses 2 numbers (1 and 0) to determine value. Our system is decimal. (0-9) Now, a 'bit' is one number from the binary system. It can either be 1 or 0. So, 8 bits means using 8 digits in binary. 1 is greater than 0, so the largest value is 11111111. (8 'one's)