If the 8 bits represent a signed number, the range is usually -128 to +127. This is -27 to 27-1.
signed magnitude
There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.
The largest possible value using 8 bits in binary is actually quite simple. Binary is a numerical system that only uses 2 numbers (1 and 0) to determine value. Our system is decimal. (0-9) Now, a 'bit' is one number from the binary system. It can either be 1 or 0. So, 8 bits means using 8 digits in binary. 1 is greater than 0, so the largest value is 11111111. (8 'one's)
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
There are 5 bits in the immediate value for an LC-3 ADD, but the first bit is needed for the sign representation. The answer is 15.
If the 8 bits represent a signed number, the range is usually -128 to +127. This is -27 to 27-1.
0xffffffffffffffff As an unsigned 64-bit integer, this represents the value 18,446,744,073,709,551,615. However, as a signed 64-bit integer, this only represents the value -1. The signed range is -9,223,372,036,854,775,808 to 9,223,372,036,854,775,807 making 0x7fffffffffffffff the largest possible positive value, and 0x8000000000000000 the smallest possible negative value.
how many bits are needed to represent decimal values ranging from 0 to 12,500?
17 bits would allow a value up to 131071.
1111111111111111 (216 - 1 = 65535)
signed magnitude
There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.
The largest possible value using 8 bits in binary is actually quite simple. Binary is a numerical system that only uses 2 numbers (1 and 0) to determine value. Our system is decimal. (0-9) Now, a 'bit' is one number from the binary system. It can either be 1 or 0. So, 8 bits means using 8 digits in binary. 1 is greater than 0, so the largest value is 11111111. (8 'one's)
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
11b which is 1*2 + 1*1 = 3 would be for two bits. But a byte is 8 bits, so 2 bytes is 16 bits. The largest binary number is [2^16 - 1], which is 65535 (base ten)
8 bits if unsigned, 9 bits if signed