The largest positive value that can be stored in 20 bits is calculated using the formula for the maximum value of an unsigned binary number, which is (2^n - 1), where (n) is the number of bits. For 20 bits, this is (2^{20} - 1 = 1,048,576 - 1 = 1,048,575). Therefore, the largest positive value that can be stored in 20 bits is 1,048,575.
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216 -1
If the 8 bits represent a signed number, the range is usually -128 to +127. This is -27 to 27-1.
The largest possible value using 8 bits in binary is actually quite simple. Binary is a numerical system that only uses 2 numbers (1 and 0) to determine value. Our system is decimal. (0-9) Now, a 'bit' is one number from the binary system. It can either be 1 or 0. So, 8 bits means using 8 digits in binary. 1 is greater than 0, so the largest value is 11111111. (8 'one's)
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
The largest binary number that can be expressed with 16 bits is 1111111111111111, which is equivalent to 65,535 in decimal. This number uses all 16 bits set to 1. In general, for an n-bit binary number, the maximum value is (2^n - 1). Thus, for 16 bits, it is (2^{16} - 1 = 65,535).