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When, in algebra, two letters are written next to each other as a term, such as m and n becoming mn, it means they are multiplied. So mn is a shorter way of writing "m times n" or "m x n"
Therefore, when m = 1 and n = 1, mn = 1 x 1 = 1
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What does m equals in mn equals m plus n?
m = n/(n-1)
Give m equals 3 and n equals 1 then m3n3 equals?
Given m equals 3 and n equals 1 then m3n3 equals?m3n3 = m*3*n*3 = 3*3*1*3 = [ 27 ]
What is the number of pairs of non-zero integers whose sum is 72 more than their product is?
Let the integers be m and n.∴ By the condition given in the question,m + n - mn = 72∴ m + n - mn = 71 + 1∴ m + n - mn - 1 = 71∴ (m - 1)(1 - n) = 71∴ (m - 1)(1 - n) = 1 × 71 = 71 × 1 = (-1) × (-71) = (-71) × (-1)Case 1:m - 1 = 1 and 1 - n = 71∴ (m, n) = (2, -70)Case 2:m - 1 = 71 and 1 - n = 1∴ (m , n) = (72, 0)This case is inadmissible as m, n are non zero integers.Case 3:m - 1 = -1 and 1 - n = -71∴ (m , n) = (0, 72)This case is inadmissible as m, n are non zero integers.Case 4:m - 1 = -71 and 1 - n = -1∴ (m, n) = (-70, 2)But as the given expression is symmetric, therefore, (2, -70) and (-70, 2) cannot be considered two different pairs.∴ We get only one solution.
What is mn - 4m - 5n 20?
mn - 4m - 5n + 20 = m(n - 4) - 5(n - 4) = (n - 4)(m - 5)
If m varies directly as n and inversely as o and m equals 20 when n equals 50 and o equals 10 find m when n equals 96 and o equals 16?
m = 24
What does m equals in mn equals m plus n?
m = n/(n-1)
How do you factor mn plus m?
m(n + 1)
Give m equals 3 and n equals 1 then m3n3 equals?
Given m equals 3 and n equals 1 then m3n3 equals?m3n3 = m*3*n*3 = 3*3*1*3 = [ 27 ]
What is m x n?
m *n (m multiplied by n) would be mn.
What is the number of pairs of non-zero integers whose sum is 72 more than their product is?
Let the integers be m and n.∴ By the condition given in the question,m + n - mn = 72∴ m + n - mn = 71 + 1∴ m + n - mn - 1 = 71∴ (m - 1)(1 - n) = 71∴ (m - 1)(1 - n) = 1 × 71 = 71 × 1 = (-1) × (-71) = (-71) × (-1)Case 1:m - 1 = 1 and 1 - n = 71∴ (m, n) = (2, -70)Case 2:m - 1 = 71 and 1 - n = 1∴ (m , n) = (72, 0)This case is inadmissible as m, n are non zero integers.Case 3:m - 1 = -1 and 1 - n = -71∴ (m , n) = (0, 72)This case is inadmissible as m, n are non zero integers.Case 4:m - 1 = -71 and 1 - n = -1∴ (m, n) = (-70, 2)But as the given expression is symmetric, therefore, (2, -70) and (-70, 2) cannot be considered two different pairs.∴ We get only one solution.
How do you factor mn - 15 plus 3m - 5n?
mn - 15 + 3m - 5n Rearranging: mn + 3m - 5n - 15 = m(n + 3) - 5(n + 3) = (m - 5)*(n + 3)
What is mn - 4m - 5n 20?
mn - 4m - 5n + 20 = m(n - 4) - 5(n - 4) = (n - 4)(m - 5)
How do you factor Mn - 4m - 5n plus 20?
mn - 4m - 5n + 20 = (mn - 5n) - (4m - 20) = n(m - 5) - 4(m - 5) = (m -5)(n - 4)
What is the multiplicative inverse of a whole number?
Let m be a whole number, then the multiplicative inverse of m is a number n such that mn=1 since 1 is the multiplicative identity. There is only one choice for n, it is 1/m since m(1/m)=1
What is the complete factored form of the following expression mn mp 3nq 3pq?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. Some possibilities are: mn + mp + 3nq + 3pq = (m+3q)*(n+p) mn - mp - 3nq + 3pq = (m-3q)*(n-p) mn + mp - 3nq - 3pq = (m-3q)*(n+p) mn - mp + 3nq - 3pq = (m+3q)*(n-p) If your question is for something else, please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc.
X over m minus y over n equals to 1 what is m?
m = xn/(n + y)
What two numbers when multiplied equals -40 and when added equals 6?
Let the numbers be 'm' & 'n' Hence mn = -40 And m + n = 6 It follows m = 6 - n Substitute (6 - n) n = -40 6n - n^2 = -40 n^2 - 6n - 40 = 0 Factor (n - 10)(n + 4) = 0 n = 10 & n = -4 => m = 6 - - 4 = 10
