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Q: What is n-4 plus 6 if n is 12?

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(n/(18*6))/n4=(n/108)/n4 ;Multiply 18 and 6(n/108)*(1/n4) ;Multiply by the reciprocal of n4, which is just 1 over n4n/(n4*108) ;The n4 will go in the bottom of the fraction1/(108n3) ;n over n4 will give you 1 over n3

n + 6 = 18 n = 12

-6 + -6 is the same as -6 - 6, so N = -12

Step 1: 4n=12 Step 2: divide both sides by 4 Step 3: 4n/4 = 12/4 Step 4: reduce Step 5: n=12/4 Step 6: n=3

n3 + 8n2 + 12n = n(n+2)(n+6)

12/n+7m=30 12/6=2 + 7x4=28

One possible answer (out of infinitely any) is t(n) = (n4 - 8n3 + 29n2 - 40n + 24)/6 for n = 1, 2, 3, etc.

6(n + 2) = 6n + 12

4n or n4

-4. One possible rule is Un = (n4 - 26n3 + 155n2 - 238n + 120)/12 for n = 1, 2, 3, ...

There are many posible answers. One of them is Un = (-n4 + 13n3 - 53n2 + 95n - 36)/6 for n = 1, 2, 3, ...

Right now, there is no solution. The sum of 2n and 12 will vary according to the value of n. If 2n + 12 = 0, then n = -6

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