4n or n4
To find all the combinations of the digits 1 through 9 and 0 taken four at a time, you would calculate the number of ways to choose 4 digits from a set of 10. This is done using the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ), where ( n ) is the total number of digits (10) and ( k ) is the number of digits to choose (4). Thus, ( C(10, 4) = \frac{10!}{4!(10-4)!} = 210 ). Therefore, there are 210 different combinations of these digits taken four at a time.
The number digits for twelve and four-tenths = 12.4
There is no such number. If the four digits are even, the entire number is even, not odd.
(The assumes that "the number" in the question is not n, although if they are they same number, this is still true.) "If the sum of the digits of the number is divisible by n, then the number itself is divisible by n" is true if n is 3 or if n is 9.
The number 3.254 contains four digits in total: three digits before the decimal point (3) and three digits after the decimal point (254). Therefore, there are four digits in the number 3.254.
There are four significant digits in the number 1.071.
The number digits for twelve and four-tenths = 12.4
There is no such number. If the four digits are even, the entire number is even, not odd.
The number 42.31 pounds has four significant digits.
(The assumes that "the number" in the question is not n, although if they are they same number, this is still true.) "If the sum of the digits of the number is divisible by n, then the number itself is divisible by n" is true if n is 3 or if n is 9.
1 is one.
n = 1, 3 or 9.
five digits number when you multiply by four is the same the number when you reversed it is 21978*4 = 87912
That works with 3 and 9.
This works with 3, and with 9.
All four of the digits given are significant digits.
If the last two digits of a number are divisible by four, the whole number is divisible by four.