The answer depends on the value of n.
PS153.N5 E4 1964 PS153.N5 E4 1964
n^2(n + 6)(n^2 - 6n + 36)
The probability of getting three fives in the first three rolls and non-fives in the next three rolls is; P(5,5,5,N5,N5,N5) = 1/6 x 1/6 x 1/6 x 5/6 x 5/6 x 5/6 = 0.002679... The number of different order in which the fives can come out is given by; 6C3 = 6!/[3!∙(6-3)!] = 20 So the probability that in 6 rolls of a fair die exactly three fives (in any order) will come out is; P(three fives any order) = (20)∙(1/6)3∙(5/6)3 = 0.05358... ~ 5.4%
Once you take out the GCF, it becomes a "difference of squares." n5(n + 1)(n - 1)
5
h
At Colibri Fashion in Highbury, N5
Get an R4 or an N5
The cast of Cell N5 - 2009 includes: Giorgi Gachechiladze as Himself - Host (2009) Zaza Papuashvili as Himself - Co-Host (2009)
C10 h16 n5 o13 p3
1234 meters
4 divided by (n5)