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The probability of getting three fives in the first three rolls and non-fives
in the
next three rolls is; P(5,5,5,N5,N5,N5) =
1/6 x 1/6 x 1/6 x 5/6 x 5/6 x 5/6
=
0.002679...
The number of different order in which the fives can come out is given by;
6C3 =
6!/[3!∙(6-3)!] =
20
So the probability that in 6 rolls of a fair die exactly three fives (in any order) will
come out is; P(three
fives any order) =
(20)∙(1/6)3∙(5/6)3 =
0.05358... ~ 5.4%
What else can I help you with?
Three dice are tossed what is the probability that the same number appears on exactly two of the three dice?
The probability is 90/216 = 5/12
What is the probability of throwing a sum of 15 on three rolls of a fair die if the first roll was a 4?
Rolling a sum of 15 on three rolls of a die, when the first roll is a 4, is the same as rolling a sum of 11 on the second and third roll. The probability of rolling 11 on two dice is 3 in 36, or 1 in 12.
What is the probability that none of the rolls is a six?
It depends on what size die you use, what its labels are and how many rolls you make. For example using a standard six-sided die and one roll, the probability of no sixes is 5/6 or ~0.83; the probability of no sixes with 25 rolls is less than 0.01 or 1%. If you used a standard d3 (three-sided die) then the probability will always be 1 or 100%, since rolling a six is impossible; but if every side has '6' on it the probability is 0, since every roll must be a 6.
What is the probability of randomly selecting a three-children family with exactly two girs?
It is 3/8.
A dice is rolled three times the probability of getting at least one odd number is?
Possible outcomes of one roll = 6.Probability of an even number on one roll = 3/6 = 0.5 .Probability of an even number on the second roll = 0.5 .Probability of an even number on the third roll = 0.5 .Probability of an even number on all three rolls = (0.5 x 0.5 x 0.5) = 0.125 = 1/8The probability of at least one odd number is the probability of not gettingan even number on all 3 rolls. That's (1 - 1/8) = 7/8 or 0.875 or 87.5% .
What is the probability of getting three fives in three rolls of a single die?
Anywhere from 0 to 1; it depends on the shape and what numbers are written on the faces.
What is the probability of rolling exactly one 4 in three rolls of a dice?
3/18 I think
What is the probability of rollling a 5 3times ina row?
With a fair die, it is 1/216 in three rolls, but the probability increases to 1 (a certainty) as the number of rolls is increased.
What is the probability that 12 rolls of a fair die will show three ones?
It is approx 0.1974
How do you get the probability of three dice rolls?
The probability of 3 specific dice rolls is the probability that each one will happen multiplied together. For instance, the probability of rolling 2 then 6 then 4 is the probability of all of these multiplied together: The probability of rolling 2 is 1/6. The probability of rolling 6 is 1/6. The probability of rolling 4 is 1/6. Multiply these together and we get the total probability as 1/216
Three dice are tossed what is the probability that the same number appears on exactly two of the three dice?
The probability is 90/216 = 5/12
Tammy is playing a game where she is trying to roll a three with a standard die if she gets a three in any of her first four rolls she wins other wise she loses what is the likelihood that Tammy wins?
To find the likelihood that Tammy wins by rolling at least one three in her first four rolls of a standard die, we can calculate the probability of losing (not rolling a three) and subtract it from 1. The probability of not rolling a three on a single roll is ( \frac{5}{6} ). Therefore, the probability of not rolling a three in four rolls is ( \left(\frac{5}{6}\right)^4 \approx 0.4823 ). Thus, the probability that Tammy wins by rolling at least one three in four rolls is ( 1 - \left(\frac{5}{6}\right)^4 \approx 0.5177 ), or about 51.77%.
What is the probability that 12 rolls of a die will show exactly three fours?
When a die is rolled once, the probability of a 4 showing up is 1/6. Apply the binomial probability for finding the probability of exactly three fours out of 12 throws of a die. n=12 (number of throws) p=1/6 (probability of a four in a single throw) x = 3 (number of times out of 12 , a four showing up) P(x=3) = 12C3 (1/6)^3 (5/6)^(12-3) = 12C3 (1/6)^3 (5/6)^9 = 0.197443
Does three sixes and two fives beat three fives and two queens?
In poker, yes.
What is the probability of getting exactly two heads in three coin tosses?
33%
William rolls a die If he gets an even number he flips a coin if he gets an odd number he rolls the die again What is the probablility?
To find the overall probability, we first look at the outcomes of rolling a die. There are three even numbers (2, 4, 6) and three odd numbers (1, 3, 5). If William rolls an even number (probability of 3/6 or 1/2), he flips a coin, which has a probability of 1/2 for heads or tails. If he rolls an odd number (also 1/2), he rolls again, and this process continues. The final probability of outcomes depends on the specific event of interest (e.g., getting heads after flipping the coin), so more context is needed to provide a specific probability.
What is the probability of throwing a sum of 15 on three rolls of a fair die if the first roll was a 4?
Rolling a sum of 15 on three rolls of a die, when the first roll is a 4, is the same as rolling a sum of 11 on the second and third roll. The probability of rolling 11 on two dice is 3 in 36, or 1 in 12.
