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Q: How many even sums can you get from rolling two dice?

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There are 9 odd sums that you can get from rolling two dice.

The most probable result of rolling two dice is a sum of seven. The probability of rolling a seven is 1 in 6 or about 0.167.All of the other possible sums have decreasing probability, all the way down to 1 in 36 or about 0.0278 for a sum of two or a sum of 12.

216/3 = 72

There are 216 permutations of three dice. Of these, 206 have a sum that is less than 16, specifically, the permutations 466, 556, 565, 566, 646, 655, 656, 664, 665, and 666 have sums that are 16 or greater - all other permutations have sums that are less than 16. The probability, then, of rolling a sum less than 16 on three dice is 206 in 216, or about 0.9537.

5

When rolling 2 dice there are 36 combinations that can occur. Sums will range from 2 to 12; sums divided by 4 are 4, 8, and 12 You can get this by dice combinations of 1 3 3 1 2 2 4 4 2 6 6 2 3 5 5 3 6 6 That is 9 ways. so odds are 9/36 = 1 in 4

The sums divisible by 3 are 3, 6, 9 and 12. These can be obtained in 2, 5, 4 and 1 ways respectively, giving 2 + 5 + 4 + 1 = 12 ways of success. There are 36 possible ways two dice can fall → probability = ways_of_success/possible_ways = 12/36 = 1/3.

The set of ordered quintuplets, the set of the sums of the outcomes, the set of the maximum values, the set of the minimum values, the set of the mean values, the set of the ranges, the set of the medians, the set of the differences of the second throw and the fifth. Plus there are very many more options.

There are eleven possible "sums of dots" if you throw two 6-sided dice. The range of possible values is from 2 (1+1) to 12 (6+6).

No. All of the permutations are equally likely, but the distinguishable combinations, and the permutations of the same sum are not. Take two dice, for instance. There are 36 permutations. The sums 2 and 12 each have only one permutation, so their probabilities are 1 in 36, each. The sum 7, however, has 6 permutations, 1-6, 2-5, 3-4, 4-3, 5-2, and 6-1, so the probability of a sum of 6 is 6 in 36, or 1 in 6.

If you roll two dice and add the numbers together, you might get 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, so there are eleven possibilities total. One is not included in this list because that would mean the first dice would roll a one and the second dice would roll a...zero? That's impossible!

8 quarters equals 2

Because each can occur in only one case. If you roll two, 6-sided dice the only way to get a sum of 2 is when they are BOTH 1's. The only way to get a sum of 12 is when they are both 6's. Thus these are the two least likely (most extreme) sums. For example there are two ways to get a sum of 3 (a 1 on one and a 2 on the other OR the reverse) or 11 (a 5 on one and a 6 on the other OR the reverse). There are even more ways to get 4 (1-3,3-1,2-2)...

No.

If the two dice are clearly distinct and the "good" sums are 3, 4, 5, 6 7, or 8, then the probability of getting good result is 25/36.

On two fair 6-sided dice: 5 out of 36 = 13.89%. Consider the two dice unique. Maybe one is black with white spots, and the other is white with black spots. There are 36 possible outcomes. You can make a table of the sums, and see that five of the outcomes have a sum of 6. Here they are:1+5, 2+4, 3+3, 4+2, 5+1

There are 36 possible outcomes when throwing 2 dices : 6 for the first dice (1,2,3,...6) and 6 for the second dice Let say that in the sums below the first number is the result of the first dice and the second number is for the result of the second dice: 2 = 1 + 1: 1 possibility 4 = 2 + 2 = 1 + 3 = 3 + 1: 3 possibilities 6 = 1 + 5 = 5 + 1 = 2 + 4 = 4 + 2 = 3 +3: 5 possibilities 1 + 3 + 5 = 9 possibilities to get 2 or 4 or 6 So the probability to get a sum of 2 or 4 or 6 is 9/36=1/4 And the probabilty of NOT rolling a sum of 2 or 4 or 6 is 1-1/4=3/4

there are 36 possible outcomes and 9 ways to get sums divible by 4, so odds are 1 in 4

1 out of 6 * * * * * Total rubbish. There are 11 possible sums - the numbers 2 to 12. So if you throw the dice 12 times, the first 11 can be different but the 12th must be a repeat.

you can make at least 25 sums

Assuming they are standard dice numbers 1-6: The minimum sum is 1 + 1 + 1 = 3 The maximum sum is 6 + 6 + = 18 So there are 18 - 3 + 1 = 16 different possible sums. But note, that some of the sums may be obtained in more than one way, for example 4 can be obtained in 3 different ways: 1 + 1 + 2, 1 + 2 + 1, 2 + 1 + 1.

The integers are 16 and 18.

Any number between 2 and 12.1+16+6

Infinitely many.

You know that the sample space of one die being rolled is {1,2,3,4,5,6}, if you roll two dice, you have a sample space with 36 elements. Here it is: (1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6) From this we can calculate many probabilities. We could look at the sums. For example what is the probability of rolling two dice and have a sum of 2? There is only one way out of 36 for this to happen so it is 1/36. Similarly, what is the chance of rolling a 1 and a 3, in either order? What is the chance of having a sum of 6? All these answers come directly from the sample space above.