(p=-15)(p=1)
p2+2pq+q2=1
rutherford
p2 + 2pq + q2 = 1q2 + 2pq + (p2 - 1) = 0q = 1/2 [ -2p plus or minus sqrt( 4p2 - 4p2 + 4 ) ]q = -1 - pq = 1 - p
The quadratic cannot be factorised. Its roots are irrational.
This quadratic expression can not be factored because its discriminant is less than zero.
p2+10d+7
P2 + 13p - 30 = 0 Answer: p= -15, p = 2
(p + 12)(p - 7) p = 7, -12
P2 + l 2 + w
p2 + 3p = p (p + 3)
If 66 = PP, then 66 = P2. After simplifying 66 = P2, the solution is: 8.124038404635960360459883568266 = P
Let p1 and p2 be the two prime numbers. Because they are prime, their divisors are div(p1) = {1,p1} and div(p2) = {1,p2}. So GCD(p1,p2) = Greatest Common Divisor of p1 and p2 = p1 if p1 equals p2 1 if p1 is different from p2