rutherford
p and q represent the frequencies of two types of alleles.
It is not an equation, but q2 meaning q^2 represents q being multiplied by itself.
If restricted to integers, then p is -1, 0 or 1. If restricted to real numbers, then any number in the interval [-1,1]. If not so restricted then any number you like.
Even
rutherford
p2 + 2pq + q2 = 1q2 + 2pq + (p2 - 1) = 0q = 1/2 [ -2p plus or minus sqrt( 4p2 - 4p2 + 4 ) ]q = -1 - pq = 1 - p
p and q represent the frequencies of two types of alleles.
It is not an equation, but q2 meaning q^2 represents q being multiplied by itself.
If restricted to integers, then p is -1, 0 or 1. If restricted to real numbers, then any number in the interval [-1,1]. If not so restricted then any number you like.
p represents the square root of the frequency of the homozygous genotype AA.
p represents the square root of the frequency of the homozygous genotype AA.
The Hardy-Weinberg Equilibrium equation: p2 + 2pq + q2 = 1 p is frequency of dominant allele A q is frequency of recessive allele a p + q always equals 1 pp or p2 is probability of AA occurring qq or q2 is probability of AA occurring 2pq is probability of Aa occurring (pq is probability of Aa, qp is probability of aA, so 2pq is probability of all heterozygotes Aa) These add up to 1 because they represent all possibilities. The frequency of the homozygous recessive genotype
In the Hardy-Weinberg equation, p2 represents the frequency of the homozygous dominant genotype in a population for a specific gene. It represents the proportion of individuals in the population that have two copies of the dominant allele.
p^2 + 2pq + q^2 = 1
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y2 of (x + y)2. But my guess is probably not!
p2 + 2pq + q2 = 1 p+q=1