Suppose the side of the square is s, then length of diagonal = s*sqrt(2)
s*sqrt(2) = 18
so s = 18/sqrt(2) = 12.7 units.
The diagonal of an 18 inch square is about 25.46 inches. (18 times the square root of 2).
18 ft Diagonal of a square is the square root of 2, times the side.
The diagonal measurement of an 18 x 18 square is: 25.46 units.
Diagonal = 18*sqrt(2) = 18*1.414214 = 25.45584 feet
A = 18 square units.
Use Pythagoras' therom: 32+32 = 18 The square root of 18 is 4.242640687 units which is the length of the diagonal.
Side = diagonal/1.5Side = 12Perimeter = 12 * 4Perimeter = 48
A square whose diagonal is the diameter of the circle. So, if it is a circle with diameter 18 units then the diagonal of the square is 18 units and so its side is 9*sqrt(2) = 12.7 units.
The perimeter = 12 feetthen the square diagonal = 12/4 = 3 feet The diagonal2 = 3x3 + 3x3= 18 feetThe diagonal = square root of 18 = 3x 21/2 feet = 3 x 1.4142 = 4.2426 feet
The diagonal of a square is not perpendicular to its side. The diagonal of a square will separate the square into two triangles. The diagonal goes from one corner to the opposite corner. Because it is a square, the diagonal and a side of the square will always form a 45-degree angle.
As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.
It's the square root of the sum 18 feet squared plus 18 feet squared. 18 feet squared is 324 square feet. 2 x 324 square feet = 648 square feet. The square root of 648 square feet is about 25.46 feet.