Use Pythagoras' therom:
32+32 = 18
The square root of 18 is 4.242640687 units which is the length of the diagonal.
4 km/h = 4,000/60 meters per minute3 minutes at this speed = 12,000/60 = 200 metersThe diagonal of a square = (length of the side) x sqrt(2) .Length of the side = (diagonal)/sqrt(2)Area = (side)2 = (diagonal)2/2 = (200)2/2 = 20,000 square meters
The diagonal of a rectangle is the third and longest side of a triangle with sides the same as those of the rectangle, so its length is the square root of the sum of the squares of the lengths of the sides of the triangle, (Pythoagoras' Theorem) which are also the sides of the rectangle. If the rectangle is 3 inches by 4 inches, then the diagonal is the square root of 3 squared (= 9) and 4 squared (= 16) so the diagonal is the square root of 16 + 9 = 25, giving it the length of 5 inches.
The perimeter = 12 feetthen the square diagonal = 12/4 = 3 feet The diagonal2 = 3x3 + 3x3= 18 feetThe diagonal = square root of 18 = 3x 21/2 feet = 3 x 1.4142 = 4.2426 feet
Each side of the square is 3 meters in length
The diagonal is 3.61cm
You draw a rectangle that has a diagonal which length is equal to twice the length of the side of the square.
Using Pythagoras' theorem each side measures 3.536 units rounded to 3 decimal places
Cool question ! Answer - half it then cube it to prove it - an example for you if cube diagonal (not square diagonal) is 100, then using pythagoras theorm the square diagonal = 70.71068, If square the square diagonal = 70.71068, then using pythagoras theorm the side length = 50 therefore the volume = 50 ^ 3 = 25000 units works with any numbers
Each side of the square is 20 inches and by using Pythagoras' theorem its diagonal is 20 times the square root of 2 which is about 28.284 inches rounded to 3 decimal places.
4 km/h = 4,000/60 meters per minute3 minutes at this speed = 12,000/60 = 200 metersThe diagonal of a square = (length of the side) x sqrt(2) .Length of the side = (diagonal)/sqrt(2)Area = (side)2 = (diagonal)2/2 = (200)2/2 = 20,000 square meters
The diagonal of a rectangle is the third and longest side of a triangle with sides the same as those of the rectangle, so its length is the square root of the sum of the squares of the lengths of the sides of the triangle, (Pythoagoras' Theorem) which are also the sides of the rectangle. If the rectangle is 3 inches by 4 inches, then the diagonal is the square root of 3 squared (= 9) and 4 squared (= 16) so the diagonal is the square root of 16 + 9 = 25, giving it the length of 5 inches.
Since Area = side length x side length And 9 = 3 x 3 The side length is 3 metres
The length of each side is 3 feet.
The longest diagonal in a cube is equal to the length of the edge, multiplied by the square root of 3.
Each side of the square is 3 meters in length
The perimeter = 12 feetthen the square diagonal = 12/4 = 3 feet The diagonal2 = 3x3 + 3x3= 18 feetThe diagonal = square root of 18 = 3x 21/2 feet = 3 x 1.4142 = 4.2426 feet
1 ft = 12 in Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 → side = diagonal ÷ √2 perimeter = 4 × side = 4 × diagonal ÷ √2 = diagonal × 2√2 = 3 ft 9 in × 2√2 = 3 × 12 + 9 in × 2√2 = 45 in × 2√2 ≈ 63.6 in = 5 × 12 + 3.4 in = 5 ft 3.4 in