√3 + √3 = 2√3
4√3 + 7√3 = (4 + 7)(√3) = 11√3
radical 3 or 6
1/(radical 13 plus 10)
2 radical 2
2 times radical 5 or about 4.472135955
4 radical 6
6 radical 2
2 radical 30
1rad5 + 2rad5 = 3rad5 3 radical 5
(a-2(ab)1/2+b)/(a-b)
Here is an example, radical 20 plus radical 5. Now radical 20 is 2(radical 5) so we can add radical 5 and 2 radical 5 and we have 3 radical 5.
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