2 radical 30
1rad5 + 2rad5 = 3rad5 3 radical 5
Here is an example, radical 20 plus radical 5. Now radical 20 is 2(radical 5) so we can add radical 5 and 2 radical 5 and we have 3 radical 5.
-2 √5 + 3 √5 = (-2 + 3) √5 = 1 √5 = √5
2 times radical 5 or about 4.472135955
√3 + √3 = 2√3
2 radical 30
1rad5 + 2rad5 = 3rad5 3 radical 5
First, note that radical 4 is 2. So 3xradical 4 is just 6, Now we have 6+2 radical 3. You can't do much with this except factor out a 2 if you want 2(3+Radical 3)
4√3 + 7√3 = (4 + 7)(√3) = 11√3
Here is an example, radical 20 plus radical 5. Now radical 20 is 2(radical 5) so we can add radical 5 and 2 radical 5 and we have 3 radical 5.
-2 √5 + 3 √5 = (-2 + 3) √5 = 1 √5 = √5
3root(6)+5root(2) you really answered it yourself!
1/(radical 13 plus 10)
2 radical 2
1 squared radical 40 is equal to 1 squared radical (4 x 10), and this become 2 squared radical 10. By adding 2 squared radical10 with 3 squared radical 10 we get 5 squared radical 10.
-3*radical(2)*radical(50) = -3*radical(2*50) = -3*radical(100) = -3*10 = -30